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deff fn [24]
3 years ago
8

If the particle is located slightly to the left of point B, its acceleration is __________.

Physics
1 answer:
Igoryamba3 years ago
7 0

(1) directed to the right

Explanation:

To the right of B, u(x) is a decreasing function & so its derivative is negative,this implies that the x component of the force on a particle at this position is positive,or that the force is directed towards right .Small deviations from equilibrium at point B causes a force to accelerate the particle away ,hence particle is in <u>unstable equilibrium.</u>

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U = 3, 9 , v = 4, 2 (a) find the projection of u onto v. (b) find the vector component of u orthogonal to v.
ExtremeBDS [4]

Answer:

(a) At U = 3, 9 , v = 4, 2, the projection of u onto v is w1=<2,8>

(b)At U = 3, 9 , v = 4, 2,  the vector component of u orthogonal to v is w2 = <4,-1>

Explanation:

A

The projection of u onto v is given by:

w1= projvu = (u⋅v||v||2)v

Given that  u= <6,7> and v=<1,4>, we can find the projection of u onto v as shown below:

w1= projvu = (u⋅v||v||2v=(<6,7>⋅<1,4><1,4>⋅<1,)

=(6⋅1+7⋅41⋅1+4⋅4)<1,4>

=3417<1,4>

=<2,8>

Part B

The vector component of u orthogonal to v is given by:

Using the given vectors and the projection found in part (a), we can find the vector component of u orthogonal to v as shown below:

w2=u−projvu

=<6,7≻<2,8>

=<(6−2),(7−8)>

=<4,−1>

To learn more about vector component, click brainly.com/question/17016695

#SPJ4

5 0
2 years ago
How does kinetic energy affect the stopping distance of a vehicle traveling at 30 mph compared to the same vehicle traveling at
Maru [420]
Well you of course have different kinetic energies with the two speeds.
Kinetic energy = (1/2)*mass*velocity^2
The vehicle's mass is the same in both cases, so we can ignore that as well as 1/2 since it's a constant.
So we have (30)^2 vs (60^2)
which is 900 vs 3600
So having 60 mph compared to 30 mph is 4 times the kinetic energy.
5 0
3 years ago
Which of the following best describes an action-reaction pair? A. The Moon Pulls on Earth, and Earth pulls back on the moon. B.
Papessa [141]
An action-reaction pair would be a pair in which one of the elements exerts a force on the other element (action), and then the other element would respond to this force by exerting another force in the opposite direction (reaction).

From the given choices, we will see that:
For choice A, the moon exerts a force on the earth by pulling it (action) and the earth responds to this force by pulling the moon (reaction in opposite direction of the action).

Therefore, the correct choice would be: 
A. <span>The Moon Pulls on Earth, and Earth pulls back on the moon.</span>
4 0
3 years ago
Read 2 more answers
If a 50 kg student is standing on the edge of a cliff. Find the student’s gravitational potential energy if the cliff is 40 m hi
Oduvanchick [21]

you can find it using the equation: potential energy=mass*gravitational acceleration*height.


energy=50kg*9.8N/kg*40m=19600Nm=19600J or 19.6kJ


Sometimes they use 10 instead of 9.8 for the g constant. 


Rember to make me Brainliest!!!

3 0
3 years ago
Give reason The SI system of unit is better than the MKS system​
egoroff_w [7]

Answer:

The SI was and is intended to extend and refine the definitions used by the MKS.

6 0
3 years ago
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