Answer:
As the object moves parallel to principle axis the image of the object will continuously moves away from the principal axis so the horizontal distance will increase
Explanation:
As the object is moving towards the lens then in that case first the image will form between the focus and double the distance of focus.
So here the image is diminished
now when the object is at large distance from from lens then its image will form at focus and it is of very small size
Now as the object comes closer to the lens till the object distance is 2F the image size will increase but smaller then object size
Now when object is between F and 2F then the image size will be more than object size and it will increase to infinite magnification
So overall we can say that as the object moves parallel to principle axis the image of the object will continuously moves away from the principal axis so the horizontal distance will increase
Answer:
<h2>20 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 10 × 2
We have the final answer as
<h3>20 N</h3>
Hope this helps you
Answer:
11.7 im pretty sure. i did the work so it should be correct
Answer:
The value is 
Explanation:
From the question we are told that
The current is 
The radius is 
The length of the wire is 
\
The resistance is 
The outer surface temperature is 
The average thermal conductivity is 
Generally the heat generated in the stainless steel wire is mathematically represented as
=> 
=> 
Generally the middle temperature is mathematically represented as
Answer:
Option (b)
Explanation:
let the weight of boat is W. In equilibrium condition, the weight of boat is equal to the buoyant force acting on the boat.
The buoyant force acting on the boat is equal to the weight of water displaced by the boat.
In case of fresh water:
Weight of the boat = weight of fresh water displaced by the boat
W = Volume of fresh water displaced x density of fresh water x g
W = V x 1 x g
W = V x g ....... (1)
In case of salt water:
Let the volume of salt water displaced is V'.
Weight of the boat = weight of salt water displaced by the boat
W = Volume of salt water displaced x density of salt water x g
W = V' x 1.02 x g ..... (2)
Equate equation (1) and equation (2), we get
V x g = V' x 1.02 x g
V' = 0.98 V
Thus, option (b) is true.
