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2 years ago

To remember the order of the quadrants, draw the

Mathematics

1 answer:

Afina-wow [57]2 years ago

7 0

Answer:

You can just write Quadrant I: All values are positive, Quadrant II: Sine is positive, Quadrant III: Tangent is positive, and Quadrant IV: Cosine is positive.

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Cuatro amigos, Andrés, Diego, Jairo y Luis juegan billar y acuerdan que aquel que pierda deberá duplicar la cantidad de dinero d

Cerrena [4.2K]

Answer:

creo que 150

Step-by-step explanation:

4 0

2 years ago

Can someone hello son please make sure it’s right :)

Sedaia [141]

Answer: x= -12

Step-by-step explanation:

These are corresponding angles which means they are the same. X+62= 50. Subtract 62 from both sides. X= -12

4 0

2 years ago

Read 2 more answers

What is the slope intercept from of the equation of the line that that passes through the points (-3, 2) and (1, 5)

viva [34]

The slope-intercept form of a line:

$y=mx+b\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\to slope\\\\b\to y-intercept$

We have:

$(-3,\ 2)\to x_1=-3,\ y_1=2\\(1,\ 5)\to x_2=1,\ y_2=5$

Substitute:

$m=\dfrac{5-2}{1-(-3)}=\dfrac{3}{4}$

$y=\dfrac{3}{4}x+b$

Put the values of coordinates of the point (1, 5) to the equation of a line:

$5=\dfrac{3}{4}(1)+b\\\\5=\dfrac{3}{4}+b\qquad|-\dfrac{3}{4}\\\\b=4\dfrac{1}{4}$

Answer: $y=\dfrac{3}{4}x+4\dfrac{1}{4}$

5 0

2 years ago

If f(x) and its inverse function, f(x), are both plotted on the same coordinate plane, where is their point of intersection?

Tcecarenko [31]

Answer:

(2,2)

Step-by-step explanation:

The graph of a function and that of its inverse should be always symmetric around the line y = x (goes at 45 degrees and crosses the origin of coordinates).

Therefore any intersection of the graphs must lie on the line y = x, which forces the x value of the intersection point to be the same as the y-value.

The only option shown where x and y have the same numerical value is the third listed option : (2,2)

7 0

3 years ago

Find the multiplicative inverse of 6 + 2i

Marina CMI [18]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2774989

________________

Find the multiplicative inverse of

$\mathsf{z=6+2i}$

________

The inverse multiplicative of $\mathsf{z=a+bi}$ is

$\mathsf{\dfrac{1}{z}}\\\\\\
=\mathsf{\dfrac{1}{a+bi}\qquad\quad(a\ne 0~~and~~b\ne 0)}\\\\\\
=\mathsf{\dfrac{1}{a+bi}\cdot \dfrac{a-bi}{a-bi}}\\\\\\
=\mathsf{\dfrac{1\cdot (a-bi)}{(a+bi)\cdot (a-bi)}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2-\,\diagup\hspace{-10}abi+\,\diagup\hspace{-10}abi-(bi)^2}}$

$=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot i^2}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot (-1)}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2+b^2}}\\\\\\\\
\therefore~~\mathsf{\dfrac{1}{a+bi}=\dfrac{a}{a^2+b^2}-\dfrac{b}{a^2+b^2}\,i\qquad\quad\checkmark}$

________

For this question,

$\mathsf{z=6+2i}$

So,

$\mathsf{\dfrac{1}{z}}\\\\\\
=\mathsf{\dfrac{1}{6+2i}}\\\\\\
=\mathsf{\dfrac{6}{6^2+2^2}-\dfrac{2}{6^2+2^2}\,i}\\\\\\
=\mathsf{\dfrac{6}{36+4}-\dfrac{2}{36+4}\,i}\\\\\\
=\mathsf{\dfrac{6}{40}-\dfrac{2}{40}\,i}$

$\therefore~~\mathsf{\dfrac{1}{z}=\dfrac{3}{20}-\dfrac{1}{20}\,i}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

6 0

3 years ago

Read 2 more answers