Question

What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)?

Answer 1

Answer:

A.  $(x+2)^2 + (y+3)^2 = 9$

Step-by-step explanation:

Equation of a circle is

$(x-x_1)^2+(y-y_1)^2=r^2$    ------------- (1)

Here

$(x_1, y_1) = (-2, -3)$

Radius is distance from center to circumference

$r=\sqrt{(-2+2)^2+(-3-0)^2}$

$r=3$

Substituting values in equation (1)

$(x+2)^2 + (y+3)^2 = 9$