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jok3333 [9.3K]
3 years ago
10

What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)?

Mathematics
1 answer:
Vlada [557]3 years ago
7 0

Answer:

A.  (x+2)^2 + (y+3)^2 = 9

Step-by-step explanation:

Equation of a circle is

(x-x_1)^2+(y-y_1)^2=r^2    ------------- (1)

Here

(x_1, y_1) = (-2, -3)

Radius is distance from center to circumference

r=\sqrt{(-2+2)^2+(-3-0)^2}

r=3

Substituting values in equation (1)

(x+2)^2 + (y+3)^2 = 9

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