What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)?
1 answer:
Answer:
A. ![(x+2)^2 + (y+3)^2 = 9](https://tex.z-dn.net/?f=%28x%2B2%29%5E2%20%2B%20%28y%2B3%29%5E2%20%3D%209)
Step-by-step explanation:
Equation of a circle is
------------- (1)
Here
![(x_1, y_1) = (-2, -3)](https://tex.z-dn.net/?f=%28x_1%2C%20y_1%29%20%3D%20%28-2%2C%20-3%29)
Radius is distance from center to circumference
![r=\sqrt{(-2+2)^2+(-3-0)^2}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B%28-2%2B2%29%5E2%2B%28-3-0%29%5E2%7D)
![r=3](https://tex.z-dn.net/?f=r%3D3)
Substituting values in equation (1)
![(x+2)^2 + (y+3)^2 = 9](https://tex.z-dn.net/?f=%28x%2B2%29%5E2%20%2B%20%28y%2B3%29%5E2%20%3D%209)
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The correct answer is 81 hours
Answer:
720
Step-by-step explanation:
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