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3 years ago

HELP I NEED THE ANSWER FAST its says true or false false ( the absolute of a number can be negative

Mathematics

2 answers:

Natali [406]3 years ago

7 0

Answer: False

Step-by-step explanation: Absolute value is the number of whole numbers the number is away from zero. So it can only be positive because you cannot have a number negative spaces away from zero

maks197457 [2]3 years ago

6 0

Answer:

False

Step-by-step explanation:

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Yw = yw what is the reason

kotegsom [21]

Answer:

The Communicative Property of Multiplication

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the probability that Geraldo, the 25-year-old you’re considering for a 30-year policy, lives to be 55 years old? Remembe

gogolik [260]

Answer: 1

Step-by-step explanation:

Given:

Geraldo current age = 25years.

Policy being considered for = 30years

Age at the end of the policy = 55years

What is the probability that Geraldo lives to be 55years.

Therefore

P ( A + B ) = 25 /55 + 30 / 55

= 5 / 11 + 6 / 11

= 11 / 11

= 1

5 0

4 years ago

HELPPP!

Anika [276]

Answer:

c. x ≈ 1.71, y ≈ 6.29, z ≈ 60.71

Step-by-step explanation:

You are at a bit of a disadvantage with this problem, because both the hint and the answer choices are incorrect.

The matrix equation is ...

$AX=B\\\\\left[\begin{array}{ccc}-1&1&0\\4&3&0\\1&-7&1\end{array}\right]\left[\begin{array}{c}x&y&z\end{array}\right]=\left[\begin{array}{c}8&12&15\end{array}\right]$

Contrary to what the hint is telling you, the multiplication by the inverse must be on the left:

$A^{-1}AX=A^{-1}B\\\\X=A^{-1}B$

Using appropriate tools to compute the inverse, this becomes ...

$\left[\begin{array}{c}x&y&z\end{array}\right]=\dfrac{1}{7}\left[\begin{array}{ccc}-3&1&0\\4&1&0\\31&6&7\end{array}\right]\left[\begin{array}{c}8&12&15\end{array}\right]\\\\\left[\begin{array}{c}x&y&z\end{array}\right]=\dfrac{1}{7}\left[\begin{array}{c}-12&44&425\end{array}\right]\approx\left[\begin{array}{c}-1.714&6.286&60.714\end{array}\right]$

The closest match is choice C.

6 0

4 years ago

You deposit $700 in an account paying 7.7% simple interest. Find the future value of the investment after 2 years. (Enter a numb

Luda [366]

Answer: The future value of the investment after 2 years is $807.8

Step-by-step explanation:

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal or amount invested.

R represents interest rate

T represents time in years

I = interest after t years

From the information given

T = 2 years

P = $700

R = 7.7%

Therefore

I = (700 × 7.7 × 2)/100

I = 10780/100

I = 107.8

The total amount in the account after 2 years would be

700 + 107.8 = $807.8

5 0

4 years ago

What is the following quotient? StartFraction 6 minus 3 (RootIndex 3 StartRoot 6 EndRoot) Over RootIndex 3 StartRoot 9 EndRoot E

Bezzdna [24]

Exponent properties help us to simplify the powers of expressions. The quotient of the given expression $\dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}}$ is (2∛3 - ∛18).

<h3>What are the basic exponent properties?</h3>

${a^m} \cdot {a^n} = a^{(m+n)}\\\\\dfrac{a^m}{a^n} = a^{(m-n)}\\\\\sqrt[m]{a^n} = a^{\frac{n}{m}}\\\\(a^m)^n = a^{m\times n}\\\\(m\times n)^a = m^a\times n^a\\\\$

Given to us

$\dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}}$

We will solve the problem using the basic exponential properties,

$\dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}}\\\\ = \dfrac{6}{\sqrt[3]{9}} - \dfrac{3(\sqrt[3]{6})}{\sqrt[3]{9}}\\\\ = (6\cdot 3^{-\frac{2}{3}}) - [3 \cdot (2 \cdot 3)^{-\frac{2}{3}}3^{-\frac{2}{3}}]\\\\= (2 \cdot 3 \cdot 3^{-\frac{2}{3}}) - [3 \cdot 2^{-\frac{2}{3}} \cdot 3^{-\frac{2}{3}}3^{-\frac{2}{3}}]\\\\$

$= [2 \cdot 3^{(1-\frac{2}{3})}] - [2^{\frac{1}{3}}\cdot 3^{(1+\frac{1}{3} - \frac{2}{3})}]\\\\= [2 \cdot 3^{(\frac{1}{3})}] - [2^{\frac{1}{3}}\cdot 3^{(\frac{2}{3})}]\\\\= 2\sqrt[3]{3} - \sqrt[3]{2}\sqrt[3]{9}\\\\=2\sqrt[3]{3} - \sqrt[3]{18}$

Hence, the quotient of the given expression $\dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}}$ is (2∛3 - ∛18).

Learn more about Exponents:

brainly.com/question/5497425

4 0

2 years ago