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3 years ago

14

Helppppppppppppppppppppppppppppppppppppppppppppp

1 answer:

Hatshy [7]3 years ago

4 0

Answer:

one solution

Step-by-step explanation:

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Solve 0.09 divided by 0.3

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Answer:

0.3.

Step-by-step explanation:

0.3|0.09

move the decimal over once on both sides.

03|.9

3

03.|.9

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Step-by-step explanation:

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The vertex of ∠ABC is<br><br> A<br> B<br> C

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Shape A can be transformed to shape B by a reflection in the x-axis followed by a translation (c/d). Find the value of c and the

bagirrra123 [75]

Answer:

$c = -6$

$d = -1$

Step-by-step explanation:

Given

See attachment for grid

Required

Find c and d

From the attachment, we have:

$a = (3,5)$ --- Point on A

$a' = (-3,-6)$ --- Corresponding point on B

When A is reflected across the x-axis, the rule is:

$(x,y) \to (x,-y)$

So, we have:

$(3,5) \to (3,-5)$

Next, is to calculate the translation from $(3,-5)$ to $(-3,-6)$

This is calculated using:

$3 + c = -3$

and

$-5 + d = -6$

So, we have:

$3 + c = -3$

$c = -3-3$

---- i.e. Shift by 6 units to the left

$-5 + d = -6$

$d = 5 - 6$

$d = -1$ --- i.e. Shift by 1 unit down

3 0

3 years ago

Assume that we have m coins. We toss each one of them n times. The probability of heads showing up for each coin isp. What’s the

olga nikolaevna [1]

Answer:

$1-(1-p^n)^m$

Step-by-step explanation:

For a coin, the probability of head showing in a single toss is $p$ .

$P(H)=p$

Its complement, the probability of not head is

$P(\Sim H)=1-p$

This is a binomial distribution. In $n$ tosses, the probability of having all heads (i.e. $n$ heads) is

$P(\text{all heads})=\binom{n}{n}p^n(1-p)^0=p^n$

Let's call this value $a$ .

For $m$ coins, we determine the probability of at least 1 coin showing all heads by first finding its complement i.e. the probability of no coin showing all heads. This is also a binomial distribution.

$P(\text{no coin showing all heads})=\binom{m}{0}a^0(1-a)^m=(1-a)^m$

$P(\text{at least 1 coin showing all heads})=1-P(\text{no coin showing all heads})$

$P(\text{no coin showing all heads})=1-(1-a)^m=1-(1-p^n)^m$

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3 years ago