Answer:
1736rev/day
Explanation:
v = Velocity
d = Diameter = 1.1 km
r = Radius = 1.1km/2 =0.55 km = 0.55 × 10^3 m
g = Acceleration due to gravity = 9.81 m/s²
g = 0.9 g
Now use the centripetal force equation
F = mg
But to balance the gravitational force
F = mv²/r...... plug in this for F
Then we have ...
mv²/r = m0.9g
Solve for v , we then have
v = √0.9gmr/m
v = √0.9gr
v = √ 0.9 × 9.81 × 0.55 × 10^3
v = 69.68465m/s
We now use the equation for frequency of a period
f = v/2 π r
f = 69.68465m/s / 2 × π0.55 × 10^3
f = 0.0201 rev/seconds
Therefore revolution for a day will be
0.0201 × 24hrs × 3600
f = 1736rev/day
<span>mass and only mass ................</span>
The answer for sure is 5 m/s
The pendulum has a kinetic energy of 330 J at the bottom of its swing.
when a pendulum oscillates, the energy at its highest point is wholly potential, since it is momentarily at rest at the highest point. The pendulum experiences acceleration which is directed towards the mean position, as a result of which its speed increases. It has maximum speed at the point which is at the bottom of its swing.
As the pendulum swings from the highest to the lowest point, the potential energy at the highest point is converted into kinetic energy.
If air resistance can be neglected, one can apply the law of conservation of energy, which states that the total energy of a system remains constant.
In this case, the potential energy of 330 J at the highest point would be equal to the kinetic energy at the bottom point.
Therefore, the kinetic energy at the bottom of its swing will be 330 J.
Answer: a) 6.67cm/s b) 1/2
Explanation:
According to law of conservation of momentum, the momentum of the bodies before collision is equal to the momentum of the bodies after collision. Since the second body was initially at rest this means the initial velocity of the body is "zero".
Let m1 and m2 be the masses of the bodies
u1 and u2 be their velocities respectively
m1 = 5.0g m2 = 10.0g u1 = 20.0cm/s u2 = 0cm/s
Since momentum = mass × velocity
The conservation of momentum of the body will be
m1u1 + m2u2 = (m1+m2)v
Note that the body will move with a common velocity (v) after collision which will serve as the velocity of each object after collision.
5(20) + 10(0) = (5+10)v
100 + 0 = 15v
v = 100/15
v = 6.67cm/s
Therefore the velocity of each object after the collision is 6.67cm/s
b) kinectic energy of the 10.0g object will be 1/2MV²
= 1/2×10×6.67²
= 222.44Joules
kinectic energy of the 5.0g object will be 1/2MV²
= 1/2×5×6.67²
= 222.44Joules
= 111.22Joules
Fraction of the initial kinetic transferred to the 10g object will be
111.22/222.44
= 1/2