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antoniya [11.8K]
3 years ago
15

Un bloque de m1= 2,00 kg está conectado con otro bloque de m2= 6,00 kg como se ve, las superficies son rugosas y su coeficiente

de rozamiento cinético es igual para las dos y de valor 0,1, el ángulo del plano inclinado es 30°. (a) Halle la aceleración de los bloques (b) halle la tensión en la cuerda (c) Si el coeficiente de rozamiento se hace igual a cero, cómo cambian las respuestas anteriores?
Physics
1 answer:
STatiana [176]3 years ago
3 0

The answer is C on edge
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A stone of mass m = 1.05 kg is released from a height of h = 2.1 m into a pool of water. At a time of t = 1.83 s after hitting t
mote1985 [20]

Answer:

Explanation:

ignoring air resistance, the kinetic energy at water impact will equal the potential energy converted

½mv² = mgh

v = √(2gh)

v = √(2(9.81)2.1) = 6.4188... m/s

after impact, an impulse will result in a change of momentum.

There is a downward impulse due to gravity equal to the weight of the stone and an upward average force due to water resistance and buoyancy force.

FΔt = mΔv

(F - mg)Δt = m(vf - vi)

(F - mg) = m(vf - vi)/Δt

F = m(vf - vi)/Δt + mg

F = m((vf - vi)/Δt + g)

F = 1.05(((½(-6.4188) - -6.4188)/ 1.83) + 9.81)

F = 12.14198...

F = 12.1 N

7 0
2 years ago
If an object is thrown upward at 128 feet per second from a height of 76 feet, its height S after t seconds is given by the foll
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<h2>a) Average velocity in first 4 seconds is 64 ft/s upward</h2><h2>b) Average velocity in second 4 seconds is 63.5 ft/s downward</h2>

Explanation:

a) Given S(t) = 76 + 128t − 16t²

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    \texttt{Velocity = }\frac{256}{4}=64ft/s

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a) Given S(t) = 76 + 128t − 16t²

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