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storchak [24]
3 years ago
15

Why does a siren have a lower pitch as it moves away from you? A The period of the sound wave is decreased B The amplitude of th

e sound wave is increased C The crests of the sound wave are farther apart D The troughs of the sound wave are spaced closer together. ​
Physics
2 answers:
Phantasy [73]3 years ago
7 0

Answer:

C

Explanation:

I think it's C because when it moves further away the sound wave is moving apart  

sweet-ann [11.9K]3 years ago
4 0

Answer:

it is letter C

there is a video explaining this

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A 500-n parachutist opens his chute and experiences an air resistance force of 800 n. the net force on the parachutist is then
Tasya [4]

Force of 500 N is acting on the parachutist.

Parachutist applies 500 N force in downward direction.

Answer:

300 N upward

Solution:

Parachutist feels air resistance of 800 N.

Thus, 800 N of force is acting in upward direction.

Total force acting on the parachutist is given by,

F_{net} = air resistance force - force of parachutist

F_{net} = 800-500

F_{net} = 300 N

Direction of force is in upward direction because the air resistance force is more than force of parachutist.

6 0
3 years ago
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¿Cuál es la velocidad del sonido en el aíre a -25°C?
Svetradugi [14.3K]

La velocidad del sonido en el aire (a una temperatura de 20 ºC) es de 343 m/s. La ecuación creada por Newton y posteriormente modificada por Laplace que permite obtener la velocidad del sonido en el aire teniendo en cuenta la variable de la temperatura es "331+(0,6 x Temperatura)".

               

8 0
3 years ago
When you stop at a railroad crossing at night, instead of correctly perceiving two red lights that flash alternately you may per
Nezavi [6.7K]
I'm pretty sure that there should be an options to choose. Anyway, I've seen this question before and I know that this is an example of <span>the phi phenomenon.</span>
7 0
3 years ago
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A car starts from rest and accelerates uniformly at 2.0 m/s2 toward the north. A second car starts from rest 4.0 s later at the
yKpoI14uk [10]

Answer:

the correct solution is 13 s

Explanation:

This is a kinematic problem, let's use accelerated rectilinear motion relationships.

For the first car it has an accelerometer of 2.0 m/s²

       x = v₀₁ t + ½ a₁ t²

The second car leaves the same point, but 4.0 seconds later

       x = v₀₂ (t-4) + ½ a₂ (t-4)²

With this form we use the same time for both cars.

The initial speeds are zero for both vehicles leave the rest, at the point where they are located has the same position

        x = ½ a₁ t²

        x = ½ a₂ (t-4)²

Let's solve

       a₁  t² = a₂ (t-4)²

      a₁/a₂ t² = t² -2 4 t + 16

      t² (1- 2.0 / 4.0) - 8 t +16

      t² 0.5 - 8 t +16 = 0

      t² -16 t + 32 = 0

Let's solve the second degree equation

     t = [16 ±√( 16² - 4 32)] / 2  

     t = ½ (16 ± 11,3)

Solutions

     t1 = 13.66 s

     t2 = 2.34 s

These are the mathematical solutions for the meeting point, but car 2 leaves after 4 seconds, so the only solution is 13.66 s

the correct solution is 13 s, if you have to select one the nearest 12s

6 0
3 years ago
How does the hydraulic garage lift helps to lift heavy weights?Explain in you words don't copy (write in the easiest way you cou
Sergeeva-Olga [200]

Answer:

this the way that hydraulic pump works:

The system of hydraulic jack lifts the heavy objects by transferring the oil from one chamber to another.

Through the suction valves into the two cylinders which creates pressure distributing the fluid equally to the points causing the objects to lift up.

hope these points helped u

any confusion then comment it

5 0
2 years ago
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