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BartSMP [9]
3 years ago
5

A pendulum has 330 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o

f its swing?
Physics
1 answer:
Naddika [18.5K]3 years ago
6 0

The pendulum has a kinetic energy of 330 J at the bottom of its swing.

when a pendulum oscillates, the energy at its highest point is wholly potential, since it is momentarily at rest at the highest point. The pendulum experiences acceleration which is directed towards the mean position, as a result of which its speed increases. It has maximum speed at the point which is at the bottom of its swing.

As the pendulum swings from the highest to the lowest point, the potential energy at the highest point is converted into kinetic energy.

If air resistance can be neglected, one can apply the law of conservation of energy, which states that the total energy of a system remains constant.

In this case, the potential energy of 330 J at the highest point would be equal to the kinetic energy at the bottom point.

Therefore, the kinetic energy at the bottom of its swing will be 330 J.

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a block measuring 20cm by 10cm by 5cm rests on a flat surface. The block has a weight of 3N. Determine the maximum pressure it e
Lady_Fox [76]
Max preassure = force / min area
= 3N / 0.1 x 0.05
= 600N/m(squared)
Copy off of the picture below itll help better, its what someone sent me when i asked this question

4 0
4 years ago
A loop of wire in the shape of a rectangle rotates with a frequency of 143 rotation per minute in an applied magnetic field of m
tatiyna

Answer:

1. e m fmax = 0.00598 Volt

2. Imax = 0.000854 Amp

Explanation:

1. Find the maximum induced emf.

e m fmax =

Given that e m fmax = N*A*B*w

N = 1

A = 2 cm^2 = 0.0002 m^2

f = 143 rotation per minute = 143/min

f = (143/min) * (1 min/60 sec) = 2.38/sec

w = 2Πf = 2 * Π * 2.38 = 14.95 rad/sec

B = 2T

e m fmax = N*A*B*w

e m fmax = 1 * 0.0002 * 2 * 14.95

e m fmax = 0.00598 Volt.

2. Find the maximum current through the bulb.

Imax = e m fmax / R

Where R is the total resistance in the circuit is 7 Ω.

Imax = 0.00598/7 = 0.000854 Amp.

Imax = 0.000854 Amp

6 0
3 years ago
The maximum water vapor that air can hold at 30°C is about 30 grams/cubic meter. If the humidity of the air is currently 6 grams
zloy xaker [14]

Answer:

20%

Explanation:

6 / 30 × 100% = 20%

6 0
4 years ago
What is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.16?
Gekata [30.6K]
(Missing figure is here: https://www.physicsforums.com/attachments/ch05-p070-jpg.149243/ )

Let's call m_1 = 1.0 kg and m_2=2.0 kg the masses of the two blocks. We can write Newton's second law for both blocks (sum of all forces acting on the block = ma). On block 1, we have two forces: the weight m_1 g pointing downwards and the tension of the string T poiting upwards. On block 2, we have the tension of the string going right and the friction \mu m_2 g going left. Therefore

m_1 g - T = m_1 a
T-\mu m_2 g = m_2 a

Summing the two equations, we find
m_1 g - \mu m_2 g = (m_1 + m_2) a
and then using \mu=0.16 we can find the acceleration:
a= \frac{m_1 g - \mu m_2 g}{m_1 + m_2}=2.22 m/s^2


6 0
3 years ago
A block rests on a ?at plate that executes vertical simple harmonic motion with a period of 0.58s.
SVETLANKA909090 [29]

Answer:

maximum amplitude  = 0.08 m

Explanation:

Given that

Time period T= 0.58 s

acceleration of gravity g= 9.8 m/s²

We know that time period of simple harmonic motion given as

T = 2π/ω

0.58 = 2π/ω

ω = 10.83rad/s

ω=angular frequency

Lets take amplitude = A

The maximum acceleration given as

a= ω² A

The maximum acceleration should be equal to g ,then block does not separate

a= ω² A

9.8 =  10.83² A

A = 0.08m

maximum amplitude  = 0.08 m

8 0
3 years ago
Read 2 more answers
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