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Ghella [55]
3 years ago
8

Which expression is equivalent ? LOOK AT THE PICTURE

Mathematics
2 answers:
victus00 [196]3 years ago
8 0

Answer:

x^ (5/3) y ^ 1/3

Step-by-step explanation:

Rewriting as exponents

(x^5y) ^ 1/3

We know that a^ b^c = a^(b*c)

x^ (5/3) y ^ 1/3

Nady [450]3 years ago
4 0

Answer:

option 2

Step-by-step explanation:

\sqrt[3]{x^{5}y}=(x^{5}y)^{\frac{1}{3}}\\\\ =x^{5*\frac{1}{3}} y^{\frac{1}{3}}\\\\ =x^{\frac{5}{3}} y^{\frac{1}{3}}

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Please help me out figure this out, simplify 5/135 btw if u can please explain
IgorC [24]
Both the numerator and the denominator can be divided by 5 to simplify the fraction:
\frac{\frac{5}{5}}{\frac{135}{5}}=\frac{1}{27}

The answer is 1/27.

6 0
2 years ago
Gary is 61 1/8 inches tall. His friends Gino and Gilbert are 56 1/2 inches tall and 63 1/8 inches tall. What’s the average heigh
Step2247 [10]
61 1/8 + 56 4/8 + 63 1/8 = 180 6/8 

<span>180 6/8 / 3 = 60 2/8 = 60 1/4 incbes</span>
8 0
3 years ago
Read 2 more answers
What half 7 1/2? Someone pls help meh​
Lina20 [59]

Not sure exactly what you mean, but heres the answers i got for this:

Exact form: 15/2

Decimal form: 7.5

3 0
3 years ago
Read 2 more answers
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by
a_sh-v [17]

Answer:

Dimension of the box is 16.1\times 7.1\times 2.45

The volume of the box is 280.05 in³.

Step-by-step explanation:          

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is L=21-2h

The width of the box is W=12-2h

The volume of the box is V=L\times W\times H

V=(21-2h)\times (12-2h)\times h

V=(21-2h)\times (12h-2h^2)

V=252h-42h^2-24h^2+4h^3

V=4h^3-66h^2+252h

To maximize the volume we find derivative of volume and put it to zero.

V'=12h^2-132h+252

0=12h^2-132h+252

Solving by quadratic formula,

h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}

h=\frac{132\pm72.99}{24}

h=2.45,8.54

Now, substitute the value of h in the volume,

V=4h^3-66h^2+252h

When, h=2.45

V=4(2.45)^3-66(2.45)^2+252(2.45)

V\approx 280.05

When, h=8.54

V=4(8.54)^3-66(8.54)^2+252(8.54)

V\approx -170.06

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is L=21-2(2.45)=16.1

The width of the box is W=12-2(2.45)=7.1

So, Dimension of the box is 16.1\times 7.1\times 2.45

6 0
3 years ago
Help please :) ..................​
brilliants [131]

Answer:

1587.6 m²

Step-by-step explanation:

A=\frac{1}{2} bh where b is the base length and h is the height (b and h on the triangle will always be perpendicular to each other)

Plug in 75.6 m as b and 42 m as h

A=\frac{1}{2} (75.6)(42)\\A=\frac{1}{2}( 3175.2)\\A=1587.6

I hope this helps!

3 0
2 years ago
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