Answer:
1. B.
2. B.
3. A.
Explanation:
1. So, the mother does not but the father does carry the gene for polydactyly. Which means that, the offspring was born Pp and, the dominant trait (P) was exposed.
2. A heterozygous trait is one that has both allele forms (in this case, d and D. If both of the parents are Dd, the offspring will also be Dd, and therefore, he has 1/2 chance of being born deaf.
3. Both you and your spouse will be heterozygous (Ee), therefore, since unattached earlobes are dominant
3.1 When two heterozygous traits are bred, you will get the following combinations: yy, Yy, Yy and YY. Which means that your offspring had a 1/4 chance of having attached earlobes, and that is what happened.
3.2 The third option is incorrect, because when you breed 2 homozygous recessive (ee) traits, all of your offspring will be homozygous recessive (ee), which means that the parents would have to be homozygous recessive, but, they cannot since the dominant trait has applied to them.
Answer:
Volume= 4 cm³
Density= 2 g/cm³
Explanation:
We have the following data:
volume= V= 8 cm³
mass= m= 16 g
The density is the mass per volume of a substance, so the density of the rock is:
density= d= 16 g/8 cm³= 2 g/cm³
When we cut the rock in half, we have a half volume and a half mass:
V= 8 cm³/2= 4 cm³
m= 16 g/2= 8 g
But the density is not altered because it is an intrisic property - it does not change with the amount of subtance. Thus, the density of a half rock is:
d = m/V= 8 g/4 cm³= 2 g/cm³
Answer:
need to be done with plenty of observation to avoid infection.
Explanation:
This technique is quite delicate because the main risk is infection. Some of the main risks are neuromuscular disease, sedation or neurological illness.
Another risk is that by passing the time, there is a difficult in respiratory, in this case, the main risk is directly to the heart, with some stoke, due to the high concentration of carbon dioxide due to the low exchange among oxygen and CO2.
Some of the indications are:
a.- Coarse crackles auscultated over trachea.
b.- Increase the respiratory pressure.
c.- Decrease tidal volume.
d.- Check the levels of oxygen in blood as in arteries.
e.- Check that patients can generate a cough.
Hope this info is useful.
