I would say Na. Oxygen has 2 valence electrons and when reacting with other molecules, the ones with the fullest or emptiest shells will react the least. Both H2 and Na are in the Alkali Metals in the first row, but since H2 has 2 molecules, it would use more oxygen than Ana
<span>We can solve this problem by assuming that the decay of
cyclopropane follows a 1st order rate of reaction. So that the
equation for decay follows the expression:</span>
A = Ao e^(- k t)
Where,
A = amount remaining at
time t = unknown (what to solve for) <span>
Ao = amount at time zero = 0.00560
M </span><span>
<span>k = rate constant
t = time = 1.50 hours or 5400 s </span></span>
The rate constant should
be given in the problem which I think you forgot to include. For the sake of
calculation, I will assume a rate constant which I found in other sources:
k = 5.29× 10^–4 s–1 (plug in the correct k value)
<span>Plugging in the values
in the 1st equation:</span>
A = 0.00560 M * e^(-5.29 × 10^–4 s–1 * 5400 s )
A = 3.218 <span>× 10^–4 M (simplify
as necessary)</span>
Answer:
12.01 g
Explanation:
Molar mass is the number of grams of a substance per mole of it.
Molar masses of elements are actually already present in the periodic table. Looking at carbon (C) on a periodic table, you'll find that its molar mass is approximately 12.01 grams.
The two solutions are
CH3COOH (acetic acid) : it is a weak acid and will dissociate less (as its Ka is very low) .Even then it will give an acidic solution. The concentration of proton will be less but it will be more than the concentration of hydroxide ions and pH of solution will be less than 7.
Thus bromothymol blue will not turn blue
NH3: ammonia
It is a weak base and will dissociate less to give hydroxide ion. EVen then it will be basic in nature. The concentration of hydroxide ion will be less but it will be more than the concentration of protons and pH of solution will be more than 7.
Thus bromothymol blue will turn blue
