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Elden [556K]
3 years ago
14

What is the mass in grams of 3.0x10^23 molecules of carbon dioxide??

Chemistry
1 answer:
Sonja [21]3 years ago
4 0
Moles of CO2 = number of molecules / 6.02x10^23. = 3x10^23/6.02x10^23 = 0.5moles. Therefore, mass of CO2 = moles x molecular mass of CO2= 0.5x44 = 22gm.
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Magnesium metal (0.100 mol) and a volume of aqueous hydrochloric acid that contains 0.500 mol of HCl are combined and react to c
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Answer:

2.24 L of hydrogen gas, measured at STP, are produced.

Explanation:

Given, Moles of magnesium metal, Mg = 0.100 mol

Moles of hydrochloric acid, HCl = 0.500 mol

According to the reaction shown below:-

Mg_{(s)} + 2HCl_{(aq)}\rightarrow MgCl_2_{(aq)} + H_2_{(g)}

1 mole of Mg reacts with 2 moles of HCl

0.100 mol of Mg reacts with 2*0.100 mol of HCl

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Available moles of HCl = 0.500 moles

Limiting reagent is the one which is present in small amount. Thus, Mg is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of Mg on reaction forms 1 mole of H_2

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Mole of H_2 = 0.100 mol

At STP,  

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Using ideal gas equation as:

PV=nRT

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1 atm × V L = 0.100 × 0.0821 L.atm/K.mol × 273.15 K  

<u>⇒V = 2.24 L</u>

2.24 L of hydrogen gas, measured at STP, are produced.

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