9514 1404 393
Answer:
a) average rate = (total distance)/(total time)
b) Rave = 2·R1·R2/(R1 +R2)
c) cheetah's average rate ≈ 50.91 mph
Step-by-step explanation:
a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...
First leg distance: AB = 70·t1 ⇒ t1 = AB/70
Second leg distance: AB = 40·t2 ⇒ t2 = AB/40
The average rate is the ratio of total distance to total time:
average rate = (AB +AB)/(t1 +t2)
average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)
average rate = 560/11 = 50 10/11 . . . mph
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No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.
b) For two rates over the same distance (as above), the average is their harmonic mean:
average rate = 2r1·r2/(r1+r2)
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c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.
Hello:
x^5 – x^4 + x^2 =x^2(x^3 - x^2 +1)
(u/v)(x)= x^2(x^3 - x^2 +1)/(-x^2)
(u/v)(x)= - (x^3 - x^2 +1) = -x^3+x^2-1 ( x : no zero)
Answer: You will need to find the x-intercepts and the vertex
Step-by-step explanation: Use the information in the factors and some formulae.
The x- intercepts are the points where the parabola crosses the x-axis. The x-axis is where y = 0
Set each factor equal to 0 and solve:
x-2=0, so x = +2 and x +4 = 0, so x = -4 (you would plot these if creating the graph)
To find the vertex you need the Vertex Formula: x = -b/2a
b is the coefficient of the x term in the middle of the quadratic equation; you can just do the O and I parts of FOIL to get b: -2x + 4x = 2x You know a = 1 because x² will have the implied (missing)(1).
Put the numbers in the Formula: x = -b/2a x = -(2)/2(1) -2/2 = -1
-1 is the "x-value" of the vertex.
The y value is the 'c' in the quadratic formula. You get that from the L part of FOIL -2 × 4 = -8 .
So, your coordinates for the vertex: ( -1, -8 )
If you were creating a graph, you would plot that point, then draw the parabola starting there and through the x-intercepts.
This is an Acute Isosceles Triangle. Hope this helps :)
