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levacccp [35]
3 years ago
6

If only of two parallel lines is perpendicular to another line the other of the two lines is ____to the third line

Mathematics
1 answer:
sergiy2304 [10]3 years ago
6 0
I think the answer is intersecting. Did you mean to type "are" instead of "is"?
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12
defon

Answer:

so the distance between the police and the library is 2x-3 where x is the distance between the police and fire and distance between the library and fire is 5 so

2x-3=5

2x=8

x=4

so C

Hope This Helps!!!

5 0
3 years ago
Gia opened two savings accounts at two diffrent banks. One account earns an annual 3.4% simple interest, and the other earns hal
dsp73

Interest from first account is :

I_1 = \dfrac{p\times r \times t}{100}\\\\I_1 = \dfrac{509\times 3.4\times 3}{100}\\\\I_1 =\$ 51.918

Interest form second account is :

I_2 = \dfrac{p\times r\times t}{100}\\\\I_2 = \dfrac{509\times 1.7\times 3}{100}\\\\I_2 =  \$25.959

So, total interest is :

I = I_1 + I_2 \\\\I = 51.918 + 25.959\\\\I = \$77.877

Therefore, total interest is $77.877 .

5 0
3 years ago
Which of the following systems is best suited for solving with the substitution method?
Agata [3.3K]

answer ...

to halp you and thank you

3 0
2 years ago
In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and
Umnica [9.8K]

Answer:

41

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0
3 years ago
I am trying to solve for x
padilas [110]
Here how i found my answer.

5 0
3 years ago
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