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3 years ago

Which choice is equivalent to the product below?

Mathematics

2 answers:

timurjin [86]3 years ago

7 0

I think the answer is C

yuradex [85]3 years ago

5 0

D . 8 100% sure .......

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What's 506.25 roundest to the nearest whole

jonny [76]

Answer:

506

Step-by-step explanation:

6 0

3 years ago

I need help please...

lutik1710 [3]

hi hun!

From what I understand, ill explain to the best of my knowledge so u understand!

First. off they asked for "proportionality" basically asking for the rate it's growing at or weeks its taking.

I see that:

Flower 1: 6 inches

Flower 2: 10 inches

Flower 3: 14 inches

The proportionality which these flowers are growing at is 4 inches every two weeks.

And I also see:

Week 3

Week 5

Week 7

When u look closer u can see that the weeks are divisible by the inches for each of the flowers and each answer u get is 2!

And also just by looking at the weeks which are 2 weeks separate if u count them.

Week 3 would be:

6/3=2

Week 5 would be:

10/5=2

Week 7 would be:

14/7=2

so the proportionality is 2! c:

- Castiel (She/They)

6 0

3 years ago

Joshua traveled 5 hours from City A to City B. The distance between the cities is 260 miles. First he traveled at the constant s

ruslelena [56]

Joshua travelled for 3 hours at the constant speed of 60 mi/h

<h3><u>Solution:</u></h3>

Given that, Joshua traveled 5 hours from City A to City B

The distance between the cities is 260 miles.

First he traveled at the constant speed of 40 mi/h, and then at the constant speed of 60 mi/h.

So, let the number of hours he travelled with 40 mi/h be "n" hours and the distance travelled be "x" miles

Then, the time in which he travelled with 60 mi/h will be 5 – n hours and distance travelled will be 260 – x miles

We have to find how many hours did he travel at the constant speed of 60 mi/h

<em><u>The relation between speed and distance is given as:</u></em>

$\text { distance }=\text { speed } \times \text { time. }$

$\begin{array}{l}{40 \mathrm{mil} / \mathrm{h} \times \mathrm{n} \text { hours }= x \text { miles }} \\\\ {\rightarrow x=40 \mathrm{n} \rightarrow(1)} \\\\ {\text { And } 60 \times(5-\mathrm{n})=260-x \text { miles }}\end{array}$

$\begin{array}{l}{\rightarrow 300-60 n=260-40 n(\text { from }(1))} \\\\ {\rightarrow 60 n-40 n=300-260} \\\\ {\rightarrow 20 n=40} \\\\ {\rightarrow n=2}\end{array}$