The calculation of the integral will give us the answer.
Amount = Int (2000e^(-0,2t))dt
With t = 0 to t = 10
A = 2000.In(e^(-0,2t))dt
Making U = -0,2t
U = -0,2t
dU/dt = d(-0,2t)/dt
dU/dt = -0,2
dU = -0,2dt
dt = dU/-0,2
_______________
Then,
A = 2000.Int (e^U).dU/-0,2
A = -10.000.Int(e^U)dU
A = -10.000.e^U
A = -10.000.e^(-0,2t) | (0,10)
A = -10.000.(e^(-2)) - [ -10.000.e^(0)]
A = -10.000.e^(-2) + 10.000
A ~ 8,646 Gallons
66% divided by 365 days is the answer i think
Answer:
b < 50. The solution has infinite solutions because any number smaller than 50 would work, and their are infinite numbers smaller than 50.
Step-by-step explanation:
Answer: See explanation
Step-by-step explanation:
We will use the formula for an arithmetic sequence which will be:
a + (n - 1)d
where a = unknown
n = 6
d = 4
We then slot them into the formula
a + (6 - 1)4 = 12
a + 5(4) = 12
a + 20 = 12
a = 12 - 20
a = -8
The 6 numbers are
1st term = -8
2nd term = -8 + 4 = -4
3rd term = -4 + 4 = 0
4th term = 0 + 4 = 4
5th term = 4 + 4 = 8
6th term = 8 + 4 = 12
