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natita [175]
3 years ago
8

Sam the squirrel monkey is a homebuilder. He is randomly choosing paint and siding colors for a house he is working on. The home

owner wants the paint and siding colors to match. If they do not match, Sam will have to redo the home which will be costly.
Sam has 6 paint options: red, green, white, black, purple, and yellow. He has 3 siding options: red, green, and white.
If Sam chooses the same color for both the paint and siding, the homeowner will be happy, and Sam will earn $1000. If Sam chooses colors that aren’t the same, he will lose $100.
What is Sam’s expected value of painting and siding this house?
Round your answer to the nearest cent.
Mathematics
2 answers:
balu736 [363]3 years ago
8 0
Long question no thanks try twenty seven
Dovator [93]3 years ago
4 0

Answer:

$83.33

Step-by-step explanation:

khan

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The Johnsons framed a family picture to hang on the wall. The perimeter of the Frame is 72 inches. Find the length of the frame
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14+14+x+x=72
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2 years ago
Which is greater 0.01 or 0.6??
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i am pretty sure it is 0.6

8 0
3 years ago
Read 2 more answers
15 feet of edging costs $24.98. How much will 28 yards cost?
GuDViN [60]

Answer:

  139.888 $

Step-by-step explanation:

Data :

   15 ft = 24.98$

   So

  1 yard = 3 ft

15ft / 3 ft = 5 yard

So  

   5 yard  = 24.98$

28 yd / 5yd = 5.6

    5.6 × 24.98 =  139.888

6 0
2 years ago
One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second
algol13

Answer:

Therefore the third container contains   \frac{735}{17}\% = 43.23 %  acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

= (V\times \frac{100+55}{100})   cubic unit.

=\frac{155}{100}V  cubic unit.

The amount of acid in first container is

=V\times \frac{25}{100}  cubic unit.

=\frac{25}{100}V  cubic unit.

The amount of acid in second container is

=(\frac{155}{100}V \times \frac{55}{100}) cubic unit.

=\frac{8525}{10000}V cubic unit.

Total amount of acid =(\frac{25}{100}V+\frac{8525}{10000}V) cubic unit.

                                   =(\frac{2500+8525}{10000}V) cubic unit.

                                   =(\frac{11025}{10000}V)cubic unit.

Total volume of mixture =(V+\frac{155}{100}V) cubic unit.

                                       =\frac{100+155}{100}V cubic unit.

                                       =\frac{255}{100}V  cubic unit.

The amount of acid in the mixture is

=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%

=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%

=\frac{735}{17}\%

Therefore the third container contains  \frac{735}{17}\%  acid.

5 0
3 years ago
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