Question

What is the midpoint of the following coordinates:

Answer 1

To find the midpoint if you have the points
(x,y) and (z,t) and you wnat to finnd the midpoint you do
midpoint=($\frac{x+z}{2} , \frac{y+t}{2}$)
so

1. (4,7) and (-3,11)
midpoint=($\frac{4-3}{2} , \frac{7+11}{2}$ )=(1/2,9)
 


2. (-8,3) ad (-6,-3)
midpoint=($\frac{-8-6}{2} , \frac{3+11}{2}$)=(-7,7)




3. (-8,5) and (-3,-5)
(-3,-5)=($\frac{-8+x}{2} , \frac{5+y}{2}$)
so
-3=$\frac{-8+x}{2}$
-6=-8+x
2=x


-5=$\frac{5+y}{2}$
-10=5+y
-15=y
B=(2,-15)


4. (9,-2) and (5,7)
(5,7)=($\frac{9+x}{2} , \frac{-2+y}{2}$)

5=$\frac{9+x}{2}$
10=9+x
1=x

7=$\frac{-2+y}{2}$
14=-2+y
16=y

A=(1,16)





1. M=(1/2,9)
2. M=(-7,7)
3.B=(2,-15)
4. A=(1,16)