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klemol [59]
3 years ago
14

g A particle is trapped in a 20 nm wide infinite potential well. What is the wavelength of the particle corresponding to n

Physics
1 answer:
malfutka [58]3 years ago
4 0

Question:

A particle is trapped in a 20 nm wide infinite potential well. What is the wavelength of the particle corresponding to n = 7 in nm?

Answer:

<em></em>\lambda_n = 5.71\ nm<em></em>

<em></em>

Explanation:

Given

L = 20nm --- the width

n = 7

Required

Determine the wavelength (\lambda)

This is calculated as:

\lambda_n = \frac{2L}{n}

Substitute values for L and n

\lambda_n = \frac{2*20nm}{7}

\lambda_n = \frac{40nm}{7}

\lambda_n = \frac{40}{7}nm

\lambda_n = 5.71428571\ nm

<em></em>\lambda_n = 5.71\ nm<em> --- approximated to 3 significant figures</em>

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<u>t = 3.74 s</u>

<u></u>

(b)

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<u></u>

(c)

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<u>Vy = 0 m/s</u>

<u></u>

(d)

Since, the horizontal component of velocity is uniform. Thus there is no acceleration in horizontal direction.

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The vertical component of acceleration is always equal to the acceleration due to gravity during projectile motion:

<u>ay = 9.8 m/s²</u>

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