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Anna71 [15]
3 years ago
12

How much does it cost to install led lights in car?

Physics
2 answers:
sineoko [7]3 years ago
7 0
Enlow charges $50 per headlight for installation.
Goryan [66]3 years ago
3 0
<span>about $137.00 (plug n play) http://store.racer-union.com try this web site they are the cheapest by about 100 dollars.</span>
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The smallest unit which maintains the physical properties of a compound is a(n) _____.
Elodia [21]
A molecule, would be the correct answer
8 0
3 years ago
Read 2 more answers
A wire with a circular cross section and a resistance R is lengthened to 9.66 times its original length by pulling it through a
damaskus [11]

Answer:

The resistance of the wire after it is stretched is 93.31R.

Explanation:

Resistance is the property of the material to oppose the current flow through it. It is given by the relation :

R = (ρl)/A

Here ρ is resistivity, l is length of wire and A is the area of the wire.

Let l₀, and A₀ are the original length and original circular cross section area of the wire. while l₁ and A₁ are the new length and new circular cross section area of the wire.

Volume of the original wire, V₀ = A₀ x l₀

Volume of the new wire, V₁ = A₁ x l₁

According to the problem. volume remain same. So,

V₀ = V₁

A₀ x l₀ = A₁ x l₁

It is given that l₁ = 9.66 x l₀. Substitute this value in the above equation;

A₀ x l₀ = A₁ x 9.66 x l₀

A₁ = A₀/9.66

Resistance of the original wire, R = (ρl₀)/A₀

Resistance of the new wire, R₁ = (ρl₁)/A₁

Substitute the value of l₁ and A₁ in the above equation.

R₁ = (ρ x l₀ x 9.66)/(A₀/9.66) = 93.31 x (ρl₀)/A₀

But (ρl₀)/A₀ = R. hence,

R₁ = 93.31 R

8 0
3 years ago
How will the electrostatic force between two electric charges change if the first charge is doubled and the second charge is onl
Vinvika [58]

Answer:

B) \frac{2}{3}

Explanation:

The electric force between charges can be determined by;

F = \frac{kq_{1} q_{2} }{r^{2} }

Where: F is the force, k is the Coulomb's constant, q_{1} is the value of the first charge, q_{2} is the value of the second charge, r is the distance between the centers of the charges.

Let the original charge be represented by q, so that;

q_{1} = 2q

q_{2} = \frac{q}{3}

So that,

F = q_{1}q_{2} x \frac{k}{r^{2} }

  = 2q x \frac{q}{3} x \frac{k}{r^{2} }

  = \frac{2q^{2} }{3} x \frac{k}{r^{2} }

  = \frac{2}{3} x \frac{kq}{r^{2} }

F = \frac{2}{3} x \frac{kq}{r^{2} }

The electric force between the given charges would change by \frac{2}{3}.

4 0
3 years ago
When 0.1375 g of solid magnesium is burned in a constant-volume bomb calorimeter, the temperature increases by 1.126°C. The heat
Bumek [7]

Answer:

-24.76 kJ/mol

Explanation:

given,

mass of solid magnesium burned = 0.1375 g

the temperature increases by(ΔT) 1.126°C

heat capacity of of bomb calorimeter (C_{cal})= 3024 J/°C

heat absorbed by the calorimeter

    q_{cal} = C_{cal}\DeltaT

    q_{cal} = 3024 \times 1.126

    q_{cal} =3405.24\ J

    q_{cal} =3.405\ kJ

heat released by the reaction

    q_{rxn} = -q_{cal}

    q_{rxn} = -3.405\ kJ

energy density will be equal to heat released by the reaction divided by the mass of magnesium

Energy density = \dfrac{-3.405}{0.1375}

Energy density = -24.76 kJ/mol

heat given off by burning magnesium is equal to -24.76 kJ/mol

6 0
3 years ago
Describe sound as a wave.​
EastWind [94]
Lol .. a what - a wave ? You just greeting somebody basically when your waving at someone I don’t really get the question but :) help it’s okay !
3 0
3 years ago
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