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nirvana33 [79]
3 years ago
13

What are spooky rays? How were they discovered? How are they related to visible light?​

Physics
1 answer:
trapecia [35]3 years ago
5 0
<h2>What are spooky rays? :Spooky rays are Halloween; Spooky mystic background light beams rays.</h2>

<h2>How was spooky rays discovered; In 1895,a German Engineer Wilhelm Röntgen, was experimenting with making cathode rays .His device was blacked out.But he noticed a piece of cardboard painted with barium platinocyanide flouresced when it was placed near the cathode ray tube.</h2>

<h2>How are they related to visible light?: This occurs when two particles are inextricably linked.</h2>

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Option C, It still explains the experimental evidence pertaining to gravity

Explanation:

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2 years ago
4 The temperature at the center of the sun is 1.55 x 10' K. Express this in degrees
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Which structure is represented by letter B?
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Sometimes referred to as the law of inertia. An object at rest stays at rest and an object in motionstays in motion with the sam
Lera25 [3.4K]

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D

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Ps- The object will stay moving in the same speed and direction.

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2 years ago
An electron is released from rest at a distance of 6.00 cm from a proton. If the proton is held in place, how fast will the elec
lana66690 [7]

Answer:

91.87 m/s

Explanation:

<u>Given:</u>

  • x = initial distance of the electron from the proton = 6 cm = 0.06 m
  • y = initial distance of the electron from the proton = 3 cm = 0.03 m
  • u = initial velocity of the electron = 0 m/s

<u>Assume:</u>

  • m = mass of an electron = 9.1\times 10^{-31}\ kg
  • v = final velocity of the electron
  • e = magnitude of charge on an electron = 1.6\times 10^{-19}\ C
  • p = magnitude of charge on a proton = 1.6\times 10^{-19}\ C

We know that only only electric field due to proton causes to move from a distance of 6 cm from proton to 3 cm distance from it. This means the electric force force does work on the electron to move it from one initial position to the final position which is equal to the change in potential energy of the electron due to proton.

Now, according to the work-energy theorem, the total work done by the electric force on the electron due to proton is equal to the kinetic energy change in it.

\therefore \textrm{Kinetic energy change}= \textrm{Change in potential energy}\\\Rightarrow \dfrac{1}{2}m(v^2-u^2)= \dfrac{kpe}{y}-\dfrac{kpe}{x}\\\Rightarrow \dfrac{1}{2}m(v^2-(0)^2)= \dfrac{kpe}{0.03}-\dfrac{kpe}{0.06}\\\Rightarrow \dfrac{1}{2}mv^2= \dfrac{100kpe}{3}-\dfrac{100kpe}{6}\\\Rightarrow \dfrac{1}{2}mv^2= \dfrac{100kpe}{6}\\

\Rightarrow v^2= \dfrac{100kpe\times 2}{6m}\\\Rightarrow v^2= \dfrac{100kpe}{3m}\\\Rightarrow v^2= \dfrac{100\times 9\times 10^9\times 1.6\times 10^{-19}\times 1.6\times 10^{-19}}{3\times 9.1\times 10^{-31}}\\\Rightarrow v^2=8.44\times 10^3\\\Rightarrow v=91.87\ m/s\\

Hence, when the electron is at a distance of c cm from the proton, it moves with a velocity of 91.87 m/s.

8 0
3 years ago
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