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FinnZ [79.3K]
4 years ago
15

A 1.00 x 10^-10 M solution of chloric acid Please help me solve this to find pH and pOH​

Chemistry
1 answer:
Svetradugi [14.3K]4 years ago
3 0

Answer: The pH of solution is 10.

The pOH of the solution is 4.

Explanation:

pH is the negative logarithm of concentration of hydrogen ion.

As given concentration of acidic solution is 1.00 \times 10^{-10} M. Therefore, pH of the solution is calculated as follows.

pH = -log [H^{+}]\\= -log (1.00 \times 10^{-10})\\= 10

The relation between pH and pOH is as follows.

pH + pOH = 14

pOH = 14 - pH

= 14 - 10

= 4

Thus, we an conclude that pH of solution is 10 and pOH of the solution is 4.

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The mass of an erlenmeyer flask is 85.135 g. after 10.00 ml of water is added to the flask, the mass of the flask and the water
BARSIC [14]
Subtracting the mass of (flask+water) from the empty flask gives:
95.023 g - 85.135 g = 9.888 grams of water
Dividing this by the given volume of 10.00 mL water gives:
9.888 grams of water / 10.00 mL of water = 0.9888 g/mL of water
Therefore, based on this sample, the density of water is 0.9888 g/mL, which is close to the usually accepted approximation of 1 g/mL.
4 0
3 years ago
Name the compound PF3
bonufazy [111]
<span>Phosphorus trifluoride (formula PF3), is a colorless and odorless gas. is similar to carbon monoxide and this is very toxic according to my research. hope this helps.</span>
8 0
3 years ago
The mole fraction of CO2 in a certain solution with H2O as the solvent is 3.6 × 10−4. What is the approximate molality of CO2 in
nataly862011 [7]

Answer: C) 0.020 m

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molality=\frac{n\times 1000}{W_s}

where,

n = moles of solute  

W_s = weight of solvent in g  

Mole fraction of CO_2 is = 3.6\times 10^{-4} i.e.3.6\times 10^{-4}  moles of CO_2 is present in 1 mole of solution.

Moles of solute (CO_2) = 3.6\times 10^{-4}

moles of solvent (water) = 1 - 3.6\times 10^{-4} = 0.99

weight of solvent =moles\times {\text {Molar mass}}=0.99\times 18=17.82g

Molality =\frac{3.6\times 10^{-4}\times 1000}{17.82g}=0.020

Thus  approximate molality of CO_2 in this solution is 0.020 m

5 0
4 years ago
How many grams of tris (mw 121.1) would you need to prepare 100 ml of a 100 mm tris solution? _________ grams?
Tems11 [23]

Molarity = (Mass/ molar mass) x (1/ volume of solution in Litres)

Mass = Molarity x molar mass x  volume of solution in Litres

Molarity of Tris = 100 mM = 0.1 M

volume of Tris sol. = 100 mL = 0.1 L

molar mass of Tris = 121.1 g/mol

Hence,

mass of Tris = Molarity of Tris x molar mass ofTris x volume of Tris solution

= 0.1 M x 121.1 g/mol x 0.1 L

= 1.211 g

mass of Tris = 1.211 g


7 0
4 years ago
A silver bar has a mass of 368g. What is the volume in cm³ of the bar? The density of silver is 19.5g/cm³.
BabaBlast [244]

Answer:

<h2>18.87 cm³</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question we have

volume =  \frac{368}{19.5}   \\  = 18.871794..

We have the final answer as

<h3>18.87 cm³</h3>

Hope this helps you

4 0
3 years ago
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