<u>Answer:</u> 0.0016 moles of copper are present in copper gluconate
<u>Explanation:</u>
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
......(1)
Given mass of copper = 0.1 g
Molar mass of copper = 63.55 g/mol
Plugging values in equation 1:

Hence, 0.0016 moles of copper are present in copper gluconate
Answer:
16.93%.
Explanation:
- If we have 1.0 mol of Fe₃Al₂(SiO₄)₃:
∴ The mass of 1.0 mol of Fe₃Al₂(SiO₄)₃ = (no. of moles of Fe₃Al₂(SiO₄)₃)(the molecular mass of Fe₃Al₂(SiO₄)₃)
∴ The mass of 1.0 mol of Fe₃Al₂(SiO₄)₃ = (1)(the molecular mass of Fe₃Al₂(SiO₄)₃) = (the molecular mass of Fe₃Al₂(SiO₄)₃).
∴ The mass of 1.0 mol of Fe₃Al₂(SiO₄)₃ = 3(atomic weight of Fe) + 2(atomic weight of Al) + 3(molecular weight of (SiO₄)₃) = 497.7474 g.
The mass of Si in 1.0 mole of Fe₃Al₂(SiO₄)₃ = 3(atomic mass of Si) = 3(28.0855 g/mol) = 84.2565 g.
∵ The mass % of Si = (the mass of Si)/(the mass of Fe₃Al₂(SiO₄)₃) = (84.2565 g)/(497.7474 g) = 16.93%.
Answer:
83.6 g
Explanation:
The limiting reactant is carbon and oxygen is in excess.
C + O₂ ⟶ CO₂
Data:
Mass of C = 22.8 g
Mass of O₂ = 78.0 g
Mass of unreacted O₂ = 17.2 g
Calculations:
Mass of O₂ reacted = 78.0 g - 17.2 g = 60.8 g
Mass of reactants (C + O₂) = 22.8 g + 60.8 g = 83.6 g
According to the Law of Conservation of Mass, the mass of the product (CO₂) equals the sum of the masses of the reactants.
The mass of CO₂ is 83.6 g.
Answer:
the answer is fe20 Hope this helps!
Explanation: