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vagabundo [1.1K]
3 years ago
11

What are silicates? what are silicates? silicates are extended arrays of silicon and nitrogen. they are the most common network

covalent atomic solids. silicates are extended arrays of sulfur and oxygen. they are the most common network covalent atomic solids. silicates are extended arrays of silicon and oxygen. they are the most common network covalent atomic solids. silicates are extended arrays of silicon and oxygen. they are the least common network ionic atomic solids?
Chemistry
2 answers:
Over [174]3 years ago
7 0

Answer:

silicates are extended arrays of silicon and oxygen.  

Explanation:

By definition, a silicate is a compound consisting of the chemical elements silicon (Si) and oxygen (O), derived from salicylic acid, which may be a salt or an ester. Of this group stand out the silicates formed by the alkali metals, constituent elements of Family IA of the periodic table, which are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs) and francium. (Fr), as these are water soluble and have various applications in industry and the laboratory. This list excludes the last two elements mentioned, due to their high molecular weight and their radioactivity. It is also relevant to report that salicylic acid is one of the derivatives of the second most abundant chemical element in the earth's crust, of the order of 27%, silicon (Si).

Georgia [21]3 years ago
3 0
The answer is b I think
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Another way to say reactants is Question 4 options:
Mamont248 [21]

Answer:

I think the answer is B or Compounds

3 0
3 years ago
If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?
ICE Princess25 [194]

<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.

<u>Explanation:</u>

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}

where,

k = rate constant = ?

t = time taken = 1.52 hrs

[A_o] = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}

To calculate the half life period of first order reaction, we use the equation:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life period of first order reaction = ?

k = rate constant = 0.2098hr^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs

Hence, the half life of the sample of silver-112 is 3.303 hours.

6 0
3 years ago
1. A contour line represents a single equal elevation: that is, all points on the same contour line have the same elevation.
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1 year ago
How many pencils are in 20 OWLS
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3 years ago
Read 2 more answers
One of the reactions in a blast furnace used to reduce iron is shown above. How many grams of Fe2O3 are required to produce 15.5
Salsk061 [2.6K]

Answer : The correct option is, (b) 22.1 g

Solution : Given,

Mass of iron = 15.5 g

Molar mass of iron = 56 g/mole

Molar mass of Fe_2O_3 = 160 g/mole

First we have to calculate the moles of iron.

\text{Moles of Fe}=\frac{\text{Mass of Fe}}{\text{Molar mass of Fe}}=\frac{15.5g}{56g/mole}=0.276moles

Now we have to calculate the moles of Fe_2O_3.

The balanced reaction is,

Fe_2O_3+3CO\rightarrow 2Fe+3CO_2

From the balanced reaction, we conclude that

As, 2 moles of iron obtained from 1 mole of Fe_2O_3

So, 0.276 moles of iron obtained from \frac{0.276}{2}=0.138 mole of Fe_2O_3

Now we have to calculate the mass of Fe_2O_3

\text{Mass of }Fe_2O_3=\text{Moles of }Fe_2O_3\times \text{Molar mass of }Fe_2O_3

\text{Mass of }Fe_2O_3=(0.138mole)\times (160g/mole)=22.08g=22.1g

Therefore, the amount of Fe_2O_3 required are, 22.1 grams.

6 0
3 years ago
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