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Katarina [22]
4 years ago
6

The table below provides some information about an unidentified element. Based on this information, the unidentified element is

best classified as which of the following?
A) a metal in group 1
B) a metal in group 14
C) a nonmetal in period 4
D) a metalloid in period 5

Chemistry
1 answer:
Leona [35]4 years ago
5 0

In the physical properties, it is mentioned that the element has 4 valence electrons. The elements in the periodic table are arranged such that, the number of valence electrons present in the neutral atoms belonging to a particular group  is equal to the group number.

Thus, the unidentified element can be best classified as a nonmetal in period 4

Ans C)

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What are the energy transformations taking place in your alarm clock
kogti [31]

Answer:

Explanation:

The clock now has potential energy. When the alarm rings, the potential energy is converted into kinetic energy and sound energy.

Alarm clock runs due to the electrical energy. Due to the electric current, the electric motor rotates the blade. It means that the electrical energy is converted into mechanical energy.

The mechanical energy finally generates vibrations which cause sound.    

Thus, energy transformation which takes place in alarm clock will follow the order-

Electrical to mechanical to sound.

5 0
3 years ago
33.75 g of copper are reacted with 117.5 g silver nitrate. How much excess reactant would be unused or left over( in grams)?
Sophie [7]
Why don’t you just look it up
4 0
3 years ago
Elements donate 2 electron to produce a cation with a 2+ charge
hammer [34]

Answer: alkaline earth metals (group-IIA)

Explanation:

The element which donates the electron is known as electropositive element and forms a positively charged ion called as cation. The element which accepts the electrons is known as electronegative element and forms a negatively charged ion called as anion.

Alkaline earth metals donate 2 valence electrons to acquire noble gas configuration.

For example: Berrylium is the first alkaline earth metal with atomic number of 4 and thus has 4 electrons

Electronic configuration of berrylium:

[Be]:4:1s^22s^2

Berrylium atom will loose two electrons to gain noble gas configuration and form berrylium cation with +2 charge.

[Be^{2+}]:2:1s^2

Thus Elements donate 2 electron to produce a cation with a 2+ charge are alkaline earth metals.

5 0
3 years ago
When 2 moles of NH3(g) react with N2O(g) to form N2(g) and H2O(g) according to the following equation, 880 kJ of energy are evol
Naily [24]

Answer:

The reaction is an exothermic reaction .

The value of q is -880 kilo Joules.

Explanation:

Exothermic reactions are defined as the reactions in which energy of reactants is more than the energy of the products. In these reactions, energy is released by the system. The total enthalpy of the reaction (\Delta H) comes out to be negative.

According to reaction, 2 moles of ammonia when reacts with 3 moles of  nitrous oxide to give 4 moles of nitrogen gas and 3 moles of water vapor, along with release of 880 kJ of heat energy.

Since, heat is evolved during the course of reaction which means that reaction is an example of Exothermic reaction.

2NH_3(g)+3N_2O(g)\rightarrow 4N_2(g)+3H_2O(g),\Delta H=-880 kJ

The reaction is an exothermic reaction .

The value of q is -880 kilo Joules.

5 0
3 years ago
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring
iren2701 [21]

Answer:

1.20 V

Explanation:

The standard cell potential is calculated from the expression

ε⁰ cell = ε⁰ oxidation + ε⁰  reduction

The species that will be reduced is the one with the higher standard reduction potential and the species that will be oxidized will be the one with the more negative reduction potential.

Thus for our question we will have

oxidation:

Pb(s)  →   Pb2+(aq) + 2 e-       ε⁰ oxidation       =  -   ε⁰  reduction

                                                                          =   - ( - 0.13 V ) = + 0.13 V

reduction    

Br2(l) + 2 e- → 2 Br-(aq)           ε⁰  reduction     = +1.07 V

ε⁰ cell = ε⁰ oxidation + ε⁰  reduction = + 0.13 V + 1.07 V  = 1.20 V

4 0
3 years ago
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