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MaRussiya [10]
3 years ago
7

How many grams of tris (mw 121.1) would you need to prepare 100 ml of a 100 mm tris solution? _________ grams?

Chemistry
1 answer:
Tems11 [23]3 years ago
7 0

Molarity = (Mass/ molar mass) x (1/ volume of solution in Litres)

Mass = Molarity x molar mass x  volume of solution in Litres

Molarity of Tris = 100 mM = 0.1 M

volume of Tris sol. = 100 mL = 0.1 L

molar mass of Tris = 121.1 g/mol

Hence,

mass of Tris = Molarity of Tris x molar mass ofTris x volume of Tris solution

= 0.1 M x 121.1 g/mol x 0.1 L

= 1.211 g

mass of Tris = 1.211 g


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A 100.0 mL sample of 0.10 M Ca(OH)2 is titrated with 0.10 M HBr. Determine the pH of the solution after the addition of 300.0 mL
Vera_Pavlovna [14]

Answer : The correct option is, (C) 1.7

Explanation :

First we have to calculate the moles of Ca(OH)_2 and HBr.

\text{Moles of }Ca(OH)_2=\text{Concentration of }Ca(OH)_2\times \text{Volume of solution}=0.10M\times 0.1L=0.01mole

\text{Moles of }HBr=\text{Concentration of }HBr\times \text{Volume of solution}=0.10M\times 0.3L=0.03mole

The balanced chemical reaction will be:

Ca(OH)_2+2HBr\rightleftharpoons CaBr_2+2H_2O

0.01 mole of Ca(OH)_2 dissociate to give 0.01 mole of Ca^{2+} ion and 0.02 mole of OH^- ion

and

0.03 mole of HBr dissociate to give 0.03 mole of H^+ ion and 0.03 mole of Br^- ion

That means,

0.02 moles of OH^- ion  neutralize by 0.02 moles of H^+ ion.

The excess moles of H^+ ion = 0.03 - 0.02 = 0.01 mole

Total volume of solution = 100 + 300 = 400 ml = 0.4 L

Now we have to calculate the concentration of H^+ ion.

\text{Concentration of }H^+=\frac{\text{Moles of }H^+}{\text{Total volume}}

\text{Concentration of }H^+=\frac{0.01mole}{0.4L}=0.025M

Now we have to calculate the pH of the solution.

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5 0
2 years ago
What is the relationship between cubic centimeters and milliliters?
Hitman42 [59]

Answer:

They are same.

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8 0
3 years ago
2N2 + O2 -------> 2 N2O
notka56 [123]

Answer:

Explanation:

Given data:

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Moles of N₂ = ?

Molecules of N₂ = ?

Mass of N₂O = ?

Moles of N₂O = ?

Atoms of N₂O = ?

Solution:

Chemical equation:

2N₂ + O₂  →  2N₂O

Number of moles of N₂:

Number of moles = mass/ molar mass

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Number of molecules of N₂:

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Now we will compare the moles of N₂ with N₂O from balance chemical equation:

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                  2             :             2

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1.74 mol

Mass of N₂O:

Mass = number of moles × molar mass

Mass =  1.74 mol ×  44 g/mol

Mass = 76.56 g

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