All categories

3 years ago

NEEDED ASAP! Show your work. Will mark brainliest!

Mathematics

2 answers:

Pani-rosa [81]3 years ago

5 0

Answer:

32 degrees

Step-by-step explanation:

Because the triangle is isosceles, 2 of its angles must equal each other:

15x - 31 = 9x + 11

---> x = 7

Plug 7 into either 15x - 31 and 9x + 11:

15(7) - 31 = 74 degrees

and

9(7) + 11 = 74 degrees

Add them together, and you get 148 degrees.

Finally, subtract 180 from 148 to get 32 degrees for angle S.

nasty-shy [4]3 years ago

3 0

NAHAHAGAHAHAHAUAHAHAHSIISKSJWJSJS

You might be interested in

Alyaa bought a bag for 10000 shillings and sold it for 6000 shillings a:Find loss b: Find the percentage loss

Vinil7 [7]

She lost 40% of the shillings

3 0

3 years ago

Read 2 more answers

The double box plot shows the test scores for Miss Robinson's second and fourth period

Gennadij [26K]

We can’t see the box plot?

4 0

3 years ago

What is the equation of the line that passes through the point (6,-3) and has a slope of -2/3?

prohojiy [21]

Answer:

y = -2/3x + 1

Step-by-step explanation:

Put -2/3x + 1 into y= on the graphing calculator and the point (6,-3) is in the table.

6 0

3 years ago

Will give brainliest, urgent

Greeley [361]

Answer:

Refer to attached

Step-by-step explanation:

<u>The answer is attached and provided below</u>

Opposite angles = Congruent
Consecutive angles = Supplementary
Diagonals = Bisects each other
Opposite sides = Parallel and congruent

4 0

3 years ago

Write two expressions with unlike denominators whose sum is x-3/x+2, I need help it is confusing for me.

skad [1K]

Answer:

$\displaystyle A=\frac{x-2}{x+3}$

$\displaystyle B=\frac{-5}{(x+3)(x+2)}$

Step-by-step explanation:

We need to find two expressions with unlike denominators what sum

$\displaystyle S=\frac{x-3}{x+2}$

Let's suppose one of the expressions is:

$\displaystyle A=\frac{x-2}{x+3}$

Now we subtract S minus A to find the other expression B:

$\displaystyle B=S-A=\frac{x-3}{x+2}-\frac{x-2}{x+3}$

Multiply the first fraction by x+3 and the second by x+2;

$\displaystyle B=(x+3)\frac{x-3}{(x+3)(x+2)}-(x+2)\frac{x-2}{(x+3)(x+2)}$

Operating:

$\displaystyle B=\frac{x^2-9}{(x+3)(x+2)}-\frac{x^2-4}{(x+3)(x+2)}$

Subtracting both fractions with like denominators:

$\displaystyle B=\frac{x^2-9-(x^2-4)}{(x+3)(x+2)}$

Simplifying:

$\displaystyle B=\frac{-5}{(x+3)(x+2)}$

Thus the two expressions are:

$\displaystyle A=\frac{x-2}{x+3}$

And

$\displaystyle B=\frac{-5}{(x+3)(x+2)}$

8 0

3 years ago