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3 years ago

It’s subtraction .Pls have a explanation math problem .

Mathematics

2 answers:

Vlada [557]3 years ago

8 0

Answer:

4 11/14

Step-by-step explanation:

9 16/14 9 turns to 8 and u add 14/14 to 2/14 16/14 then subtract 5/14

-4 5/14

4 11/14

Taya2010 [7]3 years ago

7 0

Answer:

5 4/14

Step-by-step explanation:

Ok so what we do is take the whole number away from the fractions (9 - 4)

And subtract the fractions

9/14 - 5/14 = 4/14 just remember NEVER ADD OR SUBTRACT DENOMINATORS. Now you should add the whole numbers 9 - 4 =5 now get them together 5 4/14. Theirs your answer

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Anna pays $120 per month for plano lessons. Estimate how much Anna pays

Ivanshal [37]

Answer:

1440

Step-by-step explanation:

1440 because u have multiply 120x12 because there r 12 months

3 0

3 years ago

Please help with this

GalinKa [24]

The answer is 20

Reason: so the W is 4 and the L is 6 so you do 4+4=8 then you do 6+6=12 then you add the two together and get 20

7 0

3 years ago

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

3 0

3 years ago

Jaden buys a raffle ticket. Each ticket has a 1% chance of being drawn. How likely is it that Jaden's ticket will be drawn? It d

Reika [66]

When Jaden bought the raffle ticket, he has a 1% chance of winning, which means that even if the chance is small, it's still there.

Your answer would be

It likely won't be drawn.

3 0

3 years ago

2. Tessa used the computer every day. Her mother said Tessa could only use the

Vlada [557]

Answer:

3/4 of an hour

Step-by-step explanation:

To find the leftover time, subtract the total allotted time by the time used.

First make sure they have common denominators.

1 1/2 = 3/2 = 6/4

6/4 - 3/4 = 3/4

Tessa has 3/4 of an hour left.

7 0

3 years ago