Answer:
L = s^2/(30.25Cd)
Step-by-step explanation:
In accident investigation, the speed of a vehicle can be estimated using a polynomial function that relates speed (s) to the length of skid marks (L). The drag coefficient Cd will depend on the condition of the road surface and tires, but might be expected to be between 0.7 and 0.8.
If the skid marks end in a collision, the length of the marks that might have been made can be estimated using this formula, then that length added to the actual length of marks to estimate the original speed. The speed at the point of collision can be estimated by the damage caused, and/or the movement created.
In the above formula, length is in feet, and speed is in miles per hour.
Answer:
<h2>A</h2>
Step-by-step explanation:
y > 0 - the region above the line together with that line
y ≥ 0 - the region above the line together with that line
y < 0 - the region below the line without that line
y ≤ 0 - the region below the line together with that line
We have:
y > 2 - the region above the line together with that line
y ≥ 2x - 3 - the region above the line together with that line
<em>look at the picture</em>
The common part is the solution.
If there are 24 hours a day, he hangs out 8 hours a day since 24-8-8=16
All activities are eqyal to 8/24, which simplifies to 1/3.
1/3 as a percent is 33.33...%
He should include 33.33..% three times in his circle graph.
Answer:
its 21 obviously
Step-by-step explanation:
this is because
<em>![8 {6 \times 58964 \sqrt[45 \sqrt{66x3 \times \frac{?}{?} } ]{?} \times \frac{?}{?} }^{2}](https://tex.z-dn.net/?f=8%20%7B6%20%5Ctimes%2058964%20%5Csqrt%5B45%20%5Csqrt%7B66x3%20%5Ctimes%20%5Cfrac%7B%3F%7D%7B%3F%7D%20%7D%20%5D%7B%3F%7D%20%20%5Ctimes%20%5Cfrac%7B%3F%7D%7B%3F%7D%20%7D%5E%7B2%7D%20)
</em>
<h2>
Answer:</h2><h3>
A. Domain </h3>
The domain of a function is the x-values that the graph applies to. This means that the domain is whatever x-values the graph crosses. All vertical parabolas (like the one pictured) have a domain of all reals. This is because any x-value could be plugged into the function and provide a y-value. while it may not seem like it, that graph will cover every single x-value in existence.
<h3>
B. Range</h3>
The range is similar to the domain but is for y-values. So, the range is whatever y-values the graph applies to and crosses. As you can see from the graph, there are no y-values above 1. This means the range is y≤1.
<h3>
C. Increasing Interval</h3>
A graph is increasing when the y-values are increasing. So, on the parent function of a parabola, the graph increases to the right and decreases to the left. However, this graph is inverted and shifted to the left, so the interval will also be flipped and shifted. In this case, the graph increases from -∞ to 2.
- Increasing Interval = [-∞, 2]
<h3>
D. Decreasing Interval</h3>
The decreasing interval is very similar to the increasing interval. This interval applies when the y-values are decreasing as the x-values increase. For a parabola, the increasing and decreasing intervals always meet at the x-value of the vertex, which is 2 on this graph. The y-values decrease during the interval 2 to ∞.
- Decreasing Interval = [2, ∞]
<h3>
E. Opening</h3>
The direction of a parabola is decided by the sign (+ or -) of the leading coefficient. Positive coefficients open up and negative opens down. As you can see from the graph, the sides of the parabola point downwards. This means that the leading coefficient must be negative.
<h3>
F. Min and Max</h3>
A parabola will always only have a min or a max, never both. If a graph opens up it has a min because there is one y-value which is the minimum possible y-value. Graphs that open downwards have a maximum because there is one y-value that is the largest possible. So, this graph has a maximum of 1 because that is the largest possible y-value.
