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3 years ago

3. Suppose you had titrated your vinegar sample with barium hydroxide instead of sodium hydroxide:

Chemistry

1 answer:

charle [14.2K]3 years ago

6 0

Answer:

39.6 mL

Explanation:

Step 1: Write the balanced neutralization reaction

Ba(OH)₂(aq) + 2 CH₃COOH(aq) ⟶ Ba(CH₃COO)₂(aq) + 2 H₂O(l)

Step 2: Calculate the moles corresponding to 2.78 g of CH₃COOH

The molar mass of CH₃COOH is 60.05 g/mol.

2.78 g × 1 mol/60.05 g = 0.0463 mol

Step 3: Calculate the moles of Ba(OH)₂ needed to react with 0.0463 moles of CH₃COOH

The molar ratio of Ba(OH)₂ to CH₃COOH is 1:2. The moles of Ba(OH)₂ needed are 1/2 × 0.0463 mol = 0.0232 mol.

Step 4: Calculate the volume of 0.586 M solution that contains 0.0232 moles of Ba(OH)₂

0.0232 mol × 1 L/0.586 mol = 0.0396 L = 39.6 mL

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3 years ago

G the normal range of the ph of blood is between 7.35 and 7.45; variations beyond this range have significant health implication

Fiesta28 [93]

Answer : the hydrogen ion concentrations for pH = 7.35 and pH = 7.45 are 4.46 x 10⁻⁸ M and 3.54 x 10⁻⁸ M respectively.

When the pH of a solution is less than 7, the hydrogen ion concentration is higher and therefore the solution is acidic.

On the other hand, when the pH of a solution is greater than 7, hydroxide ion concentration is higher and the solution acts as a base.

The normal pH range of blood is given as 7.35 - 7.45 which is greater than 7. That means blood is slight basic in nature.

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$pOH = - log [OH-]$

$[OH-] = 10^{-6.65}$

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Ionic product of water is written as,

$[H+] [OH-] = 1 \times 10^{-14}$

Let us plug in the calculated value of [OH-]

$[H+] = \frac{1 \times 10^{-14}}{2.24 \times 10^-7} = 4.46 \times 10^{-8} M$

The hydrogen ion concentration for pH = 7.35 is 4.46 x 10⁻⁸ M

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pOH = 6.55

[OH-] = 2.82 x 10⁻⁷

$[H+] = \frac{1 \times 10^{-14}}{2.82 \times 10^-7} = 3.54 \times 10^{-8} M$

Similarly, for pH = 7.45, we get hydrogen ion concentration of 3.54 x 10⁻⁸ M.

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