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Oliga [24]
2 years ago
9

The measure of an angle is 153.2°. What is the measure of its supplementary angle? Submit

Mathematics
1 answer:
devlian [24]2 years ago
6 0

Answer:

26.8°

Step-by-step explanation:

You find the supplementary angle by 180° - 153.2° = 26.8°

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Split the pie into 3 sections and shade only one of them

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11. Write the equation of a line in point-slope form
Vika [28.1K]

Answer:

Excuse me, wrong answer did not mean to type that. It would be C.

Step-by-step explanation:

This is because C. y - 5 = -2 (x+9) is an inequality. But, because of the slope of -2 passing through the point (-5, 9), it would be x - 9. So, C.

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3 years ago
Which is the correct input-output table for the function f(x) = 3/x + 4
Ilia_Sergeevich [38]
Do u mean the inverse ?
f-^1(x)=3/x-4
7 0
4 years ago
Please help and thank you
ycow [4]

Answer:

D) 130 workers

Step-by-step explanation:

We have the equation, <em>y = 2x + 40</em>, and <em>y, 300</em> (since the y-coordinate represents the # of bottles made), so we can solve for x, <em>the number of workers needed</em>.

Substitute: <em>300 = 2x + 40</em>

Subtract: <em>260 = 2x</em>

Divide: <em>x = 130</em>

Since x = 130 when y = 300, 130 workers are required to make 300 bottles in a day.

4 0
3 years ago
New York City is the most expensive city in the United States for lodging. The mean hotel room rate is per night (USA Today, Apr
kow [346]

Answer:

P(X

Step-by-step explanation:

Assuming a mean of $204 per night and a deviation of $55.

a. What is the probability that a hotel room costs $225 or more per night (to 4 decimals)?

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean"

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the cost per night at the hotel, and for this case we know the distribution for X is given by:

X \sim N(204,55)  

Where \mu=204 and \sigma=55

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

We are interested on this probability

P(X>225)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>225)=P(\frac{X-\mu}{\sigma}>\frac{225-\mu}{\sigma})

=P(Z>\frac{225-204}{55})=P(Z>0.382)

And we can find this probability on this way:

P(Z>0.382)=1-P(Z

8 0
3 years ago
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