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nata0808 [166]
3 years ago
11

show using dots to illustrate high population density and low population density in the boxes provided in answer to guide questi

ons ​

Chemistry
1 answer:
Nonamiya [84]3 years ago
7 0

Answer:

Just add a plenty of dots in the first one and very few dots in the second one

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PLEASE HELP IT DUE TODAY WILL GIVE 100 BRAINLY POINTS AND BRAINLYEST
inessss [21]

Answer:

1. The energy intensity from the ruler going through the air

2. This one is pretty simple, you can add or take away things. This question is just asking you to list sounds from high pitch, to lowest pitch. Here are mine:

Timer

Microwave

Mouse clicking

Dog Barking

Voice

Typing

Knocking on door

Breathing

Foot Steps

Explanation:

4 0
3 years ago
How many grams of water can be formed when 80 grams of sodium hydroxide (NaOH) reacts with an excess of sulfuric acid, H2SO4, in
podryga [215]

Answer:

36g of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction:

2NaOH + H2SO4 —> Na2SO4 + 2H2O

Next, we shall determine the mass of NaOH that reacted and the mass of H2O produced from the balanced equation. This is illustrated below:

Molar mass of NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the balanced equation = 2 x 40 = 80g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 2 x 18 = 36g.

From the balanced equation above, we can see evidently that:

80g of NaOH reacted to produce 36g of H2O.

5 0
4 years ago
How well do you think your system will digest food?
yaroslaw [1]
While it depends on what you eat so say you ate sushi or duck or what ever and you have never ate it before then your body will take a while to digest what its taking in!
7 0
4 years ago
How many litres of fluorine gas at stp can be collected from the decomposition of 90.7 g of AuF3
7nadin3 [17]

Answer: 12 L fluorine gas at STP can be collected from the decomposition of 90.7 g of AuF_3

Explanation:

The balanced decomposition reaction is shown as

2AuF_3\rightarrow 2Au+3F_2

moles of AuF_3=\frac{\text {given mass}}{\text {Molar mass}}=\frac{90.7g}{254g/mol}=0.36moles

According to stoichiometry:

2 moles of AuF_3 gives = 3 moles of flourine gas

Thus 0.36 moles of AuF_3 gives = \frac{3}{2}\times 0.36=0.54moles of flourine gas

Using ideal gas equation :

PV=nRT

P = pressure of gas = 1 atm ( at STP)

V = Volume of gas = ?

n = moles of gas = 0.54

R = gas constant = 0.0821 L atm/Kmol

T = temperature = 273 K ( at STP)

Putting the values we get :

1atm\times V=0.54mol\times 0.0821Latm/Kmol\times 273K

V=12L

Thus 12 L fluorine gas at STP can be collected from the decomposition of 90.7 g of AuF_3

6 0
3 years ago
Determine the moles of oxygen gas (O2) needed to completely react with 1.975 moles of hydrogen gas (H2).
Pavlova-9 [17]

Answer:

0.9875 mole O₂

Explanation:

Rxn => H₂ + ¹/₂O₂ => H₂O

from above reaction, 1 mol H₂ requires ¹/₂ mol O₂ then 1.975 mol H₂ requires   ¹/₂(1.975 mol)O₂ or 0.9875 mol O₂.

6 0
3 years ago
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