Answer:
If 51.8 of Pb is reacting, it will require 4.00 g of O2
If 51.8 g of PbO is formed, it will require 3.47 g of O2.
Explanation:
Equation of the reaction:
2 Pb + O2 → 2 PbO
From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO
Molar mass of Pb = 207 g
Molar mass of O2 = 32 g
Molar mass of PbO = 207 + 32 = 239 g
Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO
= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO
Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.
If 51.8 of Pb is reacting, it will require (32/414) × 51.8 g of O2 = 4.00 g of O2
Answer:
Mechanical Energy = A
Gravitational Energy = C
Nuclear Energy = B
Thermal Energy = D
Explanation:
Hope this helps you :) If any are wrong, I'm very sorry.
The word elliptical refers to regular ovals.
Answer:
A.) trans-2,3-dichloro-5-methyl-2-hexene
Explanation:
The proposed question and structure has been attached to this answer.
The<em> cis</em>- and <em>trans</em>- isomers are used to denote the alignment of the functional groups to the carbon chain side. From the diagram, we see that:
- the two chloro groups on the main compound are in opposite directions (-<em>trans</em>), and not the same sides (-<em>cis</em>)
- The bottom extended methyl group is on the 5th carbon as we count from left to right
- there's a total of 6 carbon atoms with 1 double bond on the second to third carbon.
Hence the name <u>trans-2,3-dichloro-5-methyl-2-hexene</u>
