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ehidna [41]
3 years ago
13

Quick I need help plz

Mathematics
2 answers:
Olenka [21]3 years ago
6 0

Answer:

It's answer is 1/3 .

Hope it helps have a great time :)

KonstantinChe [14]3 years ago
3 0

Answer:

\frac{3}{10}

Step-by-step explanation:

The easiest way to get the answer is to<em> convert the decimal form into its fraction form. </em>All you have to do is to take note of the <em>number of decimal places</em> in order to raise the number into the power of ten. 0.3 has one decimal place, thus, you can use 10.

  • \frac{3}{10}

Since there's no common factor, there's no cancellation needed. So, the answer is \frac{3}{10}.

Let' check.

If you divide 3 by 10, you will get the answer 0.3.

  • 3 ÷ 10 = 0.3 (It's correct)

You can get equivalent fractions to this by multiplying or dividing the numerator by the same number.

Example: \frac{3}{10} x \frac{2}{2} = \frac{6}{20}

You may also use the fraction \frac{6}{20} for your answer as this is also equivalent to 0.3.

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Calculate the slope of the line through the points V(- 6, 0) and U(4, - 2
MakcuM [25]

Answer:

<h2>hope this helps!!</h2><h3>and please let me know if I'm wrong!</h3>

7 0
3 years ago
A scale drawing has a scale of 3 in. . 1 ft. What is the scale factor?
Alex17521 [72]
The scale factor of that problem would be 3in to every 1ft
3 0
3 years ago
Read 2 more answers
A quadrilateral is graphed in the coordinate plane below. Which classification best describes the quadrilateral (parallelogram,
Ahat [919]

Answer:

Trapezoid

Step-by-step explanation:

Given quadrilateral has vertices at points A(-2,-1), B(3,13), C(15,5) and D(13,-11).

Find slopes of lines AD and BC:

\text{Slope}_{AD}=\dfrac{y_D-y_A}{x_D-x_A}=\dfrac{-11-(-1)}{13-(-2)}=\dfrac{-11+1}{13+2}=\dfrac{-10}{15}=-\dfrac{2}{3}\\ \\\text{Slope}_{BC}=\dfrac{y_C-y_B}{x_C-x_B}=\dfrac{5-13}{15-3}=\dfrac{-8}{12}=-\dfrac{2}{3}

Since the slopes are the same, lines AD and BC are parallel.

Find slopes of lines ABD and CD:

\text{Slope}_{AB}=\dfrac{y_B-y_A}{x_B-x_A}=\dfrac{13-(-1)}{3-(-2)}=\dfrac{14}{5}\\ \\\text{Slope}_{CD}=\dfrac{y_D-y_C}{x_D-x_C}=\dfrac{-11-5}{13-15}=\dfrac{-16}{-2}=8

Since the slopes are different, lines AB and CD are not parallel.

This means quadrilateral ABCD is trapezoid (two opposite sides - parallel and two another opposite sides - not parallel)

7 0
3 years ago
Using the properties of equality, find the value of x in the equation below.
Natali5045456 [20]

Answer:

-1/5 or - .2

Step-by-step explanation:

4x(2+8)= -8

(4*-.2)(2+8)= -8

-.8(2+8)= -8

-.8(10)= -8

-8=-8

8 0
3 years ago
Help as soon possible thank you ​
Sergeeva-Olga [200]

<u>Answer:</u>

The correct answer option is D. (-2, 1).

<u>Step-by-step explanation:</u>

We are given the coordinates of the square A"B"C"D" after the rule is applied and we are to find the coordinates of the vertex A.

For that, we will reverse the rule.

A" = (-5, -3)

x: - 5 + 4 = -1

y: - 3 + 1 = -2

Now we will reverse the 90 degrees counter in counter clockwise rotation:

(x, y) ---> (y, -x)

(-1. -2) ---> (-2, -(-1)) = (-2, 1)

8 0
3 years ago
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