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ehidna [41]
3 years ago
13

Quick I need help plz

Mathematics
2 answers:
Olenka [21]3 years ago
6 0

Answer:

It's answer is 1/3 .

Hope it helps have a great time :)

KonstantinChe [14]3 years ago
3 0

Answer:

\frac{3}{10}

Step-by-step explanation:

The easiest way to get the answer is to<em> convert the decimal form into its fraction form. </em>All you have to do is to take note of the <em>number of decimal places</em> in order to raise the number into the power of ten. 0.3 has one decimal place, thus, you can use 10.

  • \frac{3}{10}

Since there's no common factor, there's no cancellation needed. So, the answer is \frac{3}{10}.

Let' check.

If you divide 3 by 10, you will get the answer 0.3.

  • 3 ÷ 10 = 0.3 (It's correct)

You can get equivalent fractions to this by multiplying or dividing the numerator by the same number.

Example: \frac{3}{10} x \frac{2}{2} = \frac{6}{20}

You may also use the fraction \frac{6}{20} for your answer as this is also equivalent to 0.3.

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Answer:

Step-by-step explanation:

formula for the volume of a hexagonal pyramid is (\sqrt{3}/2)*a^{2}*h

where is is the side length, for this pyramid it's 4

and h is the height, for this pyramid it's 12

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Step-by-step explanation:

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Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as
stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

c^{2}=a^{2}+b^{2}

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

a=7\ cm\\c=13\ cm

substitute

13^{2}=7^{2}+b^{2}

Solve for b

169=49+b^{2}

b^{2}=169-49

b^{2}=120

b=\sqrt{120}\ cm

b=10.95\ cm

we have that

<em>Jayden's Work</em>

a^{2}+b^{2}=c^{2}

a=7\ cm\\b=13\ cm

substitute and solve for c

7^{2}+13^{2}=c^{2}

49+169=c^{2}

218=c^{2}

c=\sqrt{218}\ cm

c=14.76\ cm

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

<em>Sheridan's Work</em>

a^{2}+b^{2}=c^{2}

a=7\ cm\\c=13\ cm

substitute

7^{2}+b^{2}=13^{2}

Solve for b

49+b^{2}=169

b^{2}=169-49

b^{2}=120

b=\sqrt{120}\ cm

b=10.95\ cm

therefore

Sheridan's Work is correct

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Step-by-step explanation:

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