<span>Find the equation of the line parallel to the line y = 4x – 2 that passes through the point (–1, 5).
</span>y = 4x – 2 has slope = 4
<span>parallel lines have same slope so slope = 4
</span><span>passes through the point (–1, 5).
</span><span>y = mx+b
5 = 4(-1) + b
b =9
equation
y = 4x + 9
answer
The slope of y = 4x – 2 is 4
The slope of a line parallel to y = 4x – 2 is 4
The equation of the line parallel to y = 4x – 2 that passes through the point (–1, 5) is y = 4x + 9</span>
Answer:
B. Place the compass at P and draw an arc of length OP across the circle.
Below is the diagram for help.
Step-by-step explanation:
We are given with an already constructed circle of diameter 
and 
as radius.
To draw a regular hexagon(six-sided), we need to make first cut on the circle of an arc equal to radius of the circle taking any point of the diameter as center
So here, We will consider 
as a center and take an arc of length and make a cut on the circle.
This would be the first step and James need to repeat the same steps by considering the newly formed cut as center each time.
Answer:
x=1
Explain:
y=2x^2−4x+1
dy/dx=4x-4
The line of symmetry will be where the curve turns (due to the nature of the
x^2 graph.
This is also when the gradient of the curve is 0.
Therefore, let
dy/dx=0
This forms an equation such that:
4x−4=0
solve for x,
x=1
and line of symmetry falls on the line
x=1
Answer:
4. AB=4
Step-by-step explanation:
Transitive property is like substitution, or that's how I like to think of it. Since we have 2 common variables and 2 equations, we can "link them together". Replacing x with 4, you get AB=4.
