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irga5000 [103]
3 years ago
15

Four plus a number is the same as one plus five times the number

Mathematics
1 answer:
tino4ka555 [31]3 years ago
6 0
4 + x = 5x + 1


X represents the number missing
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If a(x + 1) + b(x − 1) − 2 = 0 for all real x, then a =
jek_recluse [69]

Answer:

D) 1

Step-by-step explanation:

using the distributive property we have ax+a+bx-b-2=0. because the equation is true for all real x, ax=-bx. this means a-b-2=0 and a=-b. a-b-2=0 becomes a=b+2. then we substitute a for -b and get -b=b+2 which becomes 2b=-2 so b=-1. since a=-b, a=1

7 0
3 years ago
At what value of x does graph of the following function f(x) have a vertical asymptote? F(x)= 1/x+3
kirill115 [55]

Answer:

A

Step-by-step explanation:

Given

f(x) = \frac{1}{x+3}

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 3 = 0 → x = - 3 is the vertical asymptote

7 0
3 years ago
Pls solve this qn..............ASAP<br> PLS DON'T SPAMMMMM!!
Anni [7]

Probability ( a flowering plant or fruit plant) is  \frac{13}{30} and Probability (neem plant or peepal plant) is  \frac{29}{60}.

Step-by-step explanation:

Given,

Number of neem plant = 125

Number of peepal plant = 165

Number of creppers plant = 50

Number of fruit plant = 150

Number of flowering plant = 110

To find the probability ( a flowering plant or fruit plant)

and probability ( neem or peepal)

Formula

P( A or B) = P(A) + P(B)

Probability ( a flowering plant or fruit plant) = \frac{110}{600} + \frac{150}{600}

= \frac{260}{600} = \frac{13}{30}

And,

Probability (neem plant or peepal plant) = \frac{125}{600} +\frac{165}{600}

= \frac{290}{600} = \frac{29}{60}

4 0
3 years ago
What is the distance between the points H(-5,9) and J(1,6)?
Ahat [919]

Answer:The answer would be b

Step-by-step explanation:

8 0
3 years ago
Please be kind and help me on this question.<br> WARNING: only if your good at math thank you
AVprozaik [17]

Short Answer: The first three are absolutely true. Congruency is maintained if all you are doing is shifting the figure 8 spaces away. Since the figures are congruent, their corresponding parts are equal and the statements made are always true. That's the guiding principle.


A is true. See the short answer.


B is True. You have gone 8 units away. The distance between the old G and the new one is 8 units. This is not a congruency property but it is true because it is given. You haven't altered the shape or rotatated it.


C is true by conguency. You have just shifted things 8 units. You have maintained equality and you have maintained distance between corresponding parts.


That leaves D. If the figures are regular, that will be true. If they are not regular, non corresponding external angles cannot be guaranteed to be true.

7 0
3 years ago
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