D NACL because it is ionic bond and all the others are covalent
Answer:
C) a log in the campfire turns into ashes
Answer: Volume occupied by given neon sample at standard condition is 123.84 L.
Explanation:
Given:
= 105 L,
,
= 985 torr
At standard conditions,
= 273 K,
= 760 K,
= ?
Formula used to calculate the volume is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that volume occupied by given neon sample at standard condition is 123.84 L.
This is asking for the absolute humidity. So if the relative humidity is 65 % and the air temperature is 30 then we need to have in mind the barometric pressure which will be 760. The humidity in the air will be 0.020 kg/m3. In order to know this we calculate it eith the mass of water vapour in a unit volume of air. This is a measure of the actual water vapour content of the air. the for mula would go like this: AH = Mv / V.
77.78 kJ of energy is released when 1 mol of glucose is burned, 2802.5 kJ of energy is released.
<h3>What are moles?</h3>
A mole is defined as 6.02214076 ×
of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Calculate the moles of 5.00g of glucose.
Given mass = 5.00g
The molar mass of glucose = 180.156 g/mol


Moles =0.02775372455
The quantity of energy released to a person by eating 5.00g of glucose in a candy.
0.02775372455 x 2802.5 kJ
77.77981305 kJ =77.78 kJ
Hence, 777.78 kJ of energy is released.
Learn more about moles here:
brainly.com/question/8455949
#SPJ1