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3 years ago

These are the photos for part A

Chemistry

1 answer:

Alla [95]3 years ago

6 0

Answer:

Explanation:

For part C, this should be what the graph looks like.

The reactants should have higher energy that the products so that it can release energy. Recall the reaction is N2 + 3H2 => 2NH3 + energy, making it exothermic. Apparently, you are supposed to adjust the energy diagram on the simulation so that 20% of the reactants become the products.

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1) Calculate the empirical formula of a compound with 36g of carbon and 96g of oxygen.

grandymaker [24]

Answer:

C4H6

Explanation:

See attached table

Convert each of the masses into moles by dividing the mass by the molar mass of that element. That yields 3.83 moles of C and 6 moles of O. I rounded up the C to 4 moles to result in an empirical formula of C4H6

5 0

2 years ago

Hydroxylamine hydrochloride is a powerful reducing agent which is used as a polymerization catalyst. It contains 5.80 mass % H,

ludmilkaskok [199]

Answer: The empirical formula for the given compound is $H_{4}O_1N_1Cl_1=H_4NOCl$

Explanation:

We are given:

Percentage of H = 5.80 %

Percentage of O = 23.02 %

Percentage of N = 20.16 %

Percentage of Cl = 51.02 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of H = 5.80 g

Mass of O = 23.02 g

Mass of N = 20.16 g

Mass of Cl = 51.02 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{5.80g}{1g/mole}=5.80moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{23.02g}{16g/mole}=1.44moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{20.16g}{14g/mole}=1.44moles$

Moles of Chlorine = $\frac{\text{Given mass of Chlorine}}{\text{Molar mass of Chlorine}}=\frac{51.02g}{35.5g/mole}=1.44moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.44 moles.

For Hydrogen = $\frac{5.80}{1.44}=4.03\approx 4$

For Oxygen = $\frac{1.44}{1.44}=1$

For Nitrogen = $\frac{1.44}{1.44}=1$

For Chlorine = $\frac{1.44}{1.44}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of H : O : N : Cl = 4 : 1 : 1 : 1

Hence, the empirical formula for the given compound is $H_{4}O_1N_1Cl_1=H_4NOCl$

3 0

3 years ago

10. Which statement about cellular respiration in plants and animals is true?

kogti [31]

Answer:

Ⓑ Both plants and animals release energy from glucose/sugar in cellular respiration.

3 0

3 years ago

Read 2 more answers

The number of nucleons of an isotope represents the total number of..

Elza [17]

Answer:

The mass number (A), also called atomic mass number or nucleon number, is the total number of protons and neutrons (together known as nucleons) in an atomic nucleus. The mass number is different for each different isotope of a chemical element.

3 0

2 years ago

10 To become positively charged, an atom must: A Galn a proton B Lose a proton C С. Galn an electron D Lose an electron }

Studentka2010 [4]

Answer:

D: lose an electron

Explanation:

when an atom loses an electron it's positively charged and when it gain an electron it is negatively charged

6 0

3 years ago