Answer:
Frequency, f = 0.6 Hz
Explanation:
We have,
Number of waves passing through a point are 3
Time for which the waves are passing is 5 seconds
It is required to find the frequency of a wave. The frequency of a wave is defined as the no of waves per unit time. So,
So, the frequency of a wave is 0.6 Hz.
Answer:
Freezing. When a liquid is cooled, the average energy of the molecules decreases. At some point, the amount of heat removed is great enough that the attractive forces between molecules draw the molecules close together, and the liquid freezes to a solid.
Note how temperature effects the motion of the atoms or molecules in a liquid. As the temperature of a solid, liquid or gas increases, the particles move more rapidly. As the temperature falls, the particles slow down. If a liquid is cooled sufficiently, it forms a solid.
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Answer:
The unknown amount of potassium chloride is 13.6 grams.
Explanation:
The reaction of 14 grams of KNO₃ with KCl produces a total mass of 27.6 grams of the products.
The law of conservation of mass tells us that the total mass of the reactants must be the same that the total mass of the products. So, we can find the mass of KCl as follows:
Where <em>r</em> is for reactants and <em>p </em>is for products
Therefore, the unknown amount of potassium chloride is 13.6 grams.
I hope it helps you!
The heat of the reaction, in kJ, when 4.18 g of the hydrocarbon are combusted 775.70 kJ.
The heat energy is given as :
q = m c ΔT + Ccal ΔT
q = ( 974 g× 4.184 ×6.9) + 624 ×6.9
q = 32424.59 J
moles of hydrocarbon = 0.0418 mol
heat of combustion = 32424.59 J / 0.0418 mol
= 775707.89 J
= 775.70 kJ
Thus, A 4.18 g sample of a hydrocarbon is combusted in a bomb calorimeter that contains 974 g of water. the temperature of the water increases by 6.9 °C when the hydrocarbon is combusted. the calorimeter constant for the calorimeter was determined to be 624 J/°C. what is the heat of the reaction is 775.70 kJ.
To learn more about calorimeter here
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75.7 grams.
Convert moles to grams using this:
Moles • grams/1 mole = grams
(Grams is over 1 mole)
