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3 years ago

Which expression is equivalent to g+g+g+g+g+g? Plz help meh know!

Mathematics

1 answer:

il63 [147K]3 years ago

8 0

I believe the expression that is equivalent to g+g+g+g+g+g is 6g. I'm not sure as you never sent a picture whatsoever.

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Find the missing angles

lora16 [44]

Let's find a.

We are given a right angle which is 90° and an angle marked by "a" next to it. We know that when they are added together, they make a supplementary angle so we can make a equationa and solve.

90 + a = 180

a = 90°

Let's find b.

By looking at the graph, we can tell that the angle "b" and the angle that measures 163° is the same. Thus, b = 163°.

Let's find c.

Using what we did for a, we can solve for c using what we got for b. We can make an equation and solve.

163 + b = 180

c = 27°

Let's find d.

Using the angle that measures 70°, we can solve it like we did with a and c.

70 + d = 180

d = 110°

Let's find e.

Now that we know what d equals, we know that d and e make a supplmentary angle. So, make an equation and solve.

110 + e = 180

e = 70°

Best of Luck!

5 0

3 years ago

The owner of a new pet store wishes to display tropical fish in display tanks. The above table shows the species that cannot liv

Pepsi [2]

Answer:

The minimum number of different tanks needed to safely house all the fish is:

3 tanks.

Step-by-step explanation:

To identify the minimum number of different tanks, we're gonna concentrate in a fish species, in this case can be the A: as you see in the table, the A species can live with all the fish excepting the F and G, by their side, the F and G can't live together , by this reason, this three species must live in a different tank, in the next form:

Tank 1: A
Tank 2: F
Tank 3: G

Now the B species, it can live with A, F and G, but for this example we can put in the tank 1 (the tank of the A species). The C especies can live with A, F and G, but how we have A and B together, we're gonna put the C especies in the tank 3 (the tank of the G especies). The D species can live with A and G, we're gonna put in the tank 1 because can live with B species too. The E species can live with A and F, we're gonna put in the tank 2 (the tank of the F species) because the E species can't live with D that is in the in the tank 1. Al last, the H species just can live with A, E, F, and H species, by this reason, the only tank that can be put is the tank 2. In this form, the order is the next:

Tank 1: A, B, D.
Tank 2: F, E, H.
Tank 3: G, C.

And the owner of the pet store must buy three different tanks to display these tropical fish.

5 0

3 years ago

Much appriciated if helping

Goryan [66]

Answer:

i think it is 3

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Which inequality is represented by the graph? y≥35x−1.5 y≤35x−1.5 y<35x−1.5 y>35x−1.5

Setler79 [48]

Answer:

y > 0.6x - 1.5

Step-by-step Explanation:

We need two points, to get to the equation of the graph.

Since we've got the following equation for two points (x1, y1), (x2, y2):-

$\boxed{ \mathsf{ \red{y - y_{1} = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1}) }}}$

okay soo

I found two points that lie on this graph, not on the shaded region but yeah the dotted line which defines the graph.

one point is (0, -1.5) which lies on the y axis(the point where the dotted line touches the y axis)

other point is (2.5, 0) and this lies on the x axis

placing these points in the place of (x1, y1) and (x2, y2) in the above mentioned equation

$\mathsf{\implies y - ( - 1.5) = \frac{0 -( - 1.5)}{2.5 -0 } (x -0 )}$

you can take any one as (x1, y1) or (x2, y2).

so upon solving the above equation we get

$\mathsf{\implies (y + 1.5) = \frac{0 + 1.5}{2.5 } (x )}$

$\mathsf{\implies y + 1.5 = \frac{ 1.5}{2.5 } x }$

$\mathsf{\implies y + 1.5 = \frac{ \cancel{1.5}\:\:{}^3}{\cancel{2.5}\:\:{}^5 } x }$

$\mathsf{\implies y + 1.5 = \frac{ 3}{5 } x }$

multiplying both sides by 5

$\mathsf{5y + 7.5 = 3x}$

okay so this is the required equation of the dotted line

now we'll find the inequality

for this check whether the origin (0,0) lies under the shaded region or not

in this case it does

replacing x and y with 0

$\mathsf{\implies5(0) + 7.5 = 3(0)}$

$\mathsf{\implies0 + 7.5 = 0}$

this is absurd, 7.5 is not equal to 0 so we're gonna replace that equals sign with that of inequality

7.5 is greater than 0! so,

$\mathsf{\implies7.5 > 0}$

this goes for the whole equation, since we didnt swap any thing from left to right side of the equation or vice versa we can use this sign, to obtain the required inequality

$\mathsf{5y + 7.5 > 3x}$

dividing this inequality by 5, since there's no co-efficient in front of y in the given answers

we get

y + 1.5 > 0.6x

taking 1.5 to the RHS

that is the last option

5 0

3 years ago

A parabola can be drawn given a focus of (-11, -2) and a directrix of x= -3

fgiga [73]

Check the picture below, so the parabola looks more or less like that.

now, the vertex is half-way between the focus point and the directrix, so that puts it where you see it in the picture, and the horizontal parabola is opening to the left-hand-side, meaning that the distance "P" is negative.

$\textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\supset}\qquad \stackrel{"p"~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\begin{cases} h=-7\\ k=-2\\ p=-4 \end{cases}\implies 4(-4)[x-(-7)]~~ = ~~[y-(-2)]^2 \\\\\\ -16(x+7)=(y+2)^2\implies x+7=-\cfrac{(y+2)^2}{16}\implies x=-\cfrac{1}{16}(y+2)^2-7$

8 0

2 years ago