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3 years ago

How many moles of hydrogen are required to react with 4.6 x 10 22 molecules of nitrogen?

Chemistry

1 answer:

V125BC [204]3 years ago

8 0

Answer: 6 moles

Take a look at the balanced chemical equation for this synthesis reaction

N 2(g] + 3 H 2(g] → 2 NH 3(g]

Notice that you have a 1:3 mole ratio between nitrogen gas and hydrogen gas. This means that, regardless of how many moles of nitrogen gas you have, the reaction will always consume twice as many moles of hydrogen gas.

So, if you have 2 moles of nitrogen taking part in the reaction, you will need

2 moles N 2 ⋅ 3 moles H 2 /1 mole N 2 = 6 moles H 2

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2.3 moles of CaBr2 contains how many molecules

kkurt [141]

Avogadro's law states that in every mole of a substance, there are $6.022 \times 10^{23}$ molecules.

This means that in 2.3 moles, there are $2.3(6.022 \times 10^{23})=\boxed{1.4 \times 10^{24} \text{ (to 2 sf)}}$

7 0

1 year ago

ANSWER PLEASE LIMIT TIME !!!! <br> What do earth and space have alike ?

marishachu [46]

Answer:

Great question, here are a few! (╯°▽°)╯ ┻━┻

Explanation:

1. Atmosphere, The first difference between the Earth and space is the atmosphere.

2. radiation (high level of dangerous particles)!

3. gravity (weightlessness in space)

4 0

2 years ago

Enter the condensed electron configuration for cu4+.express your answer in condensed form, in order of increasing orbital energy

Marysya12 [62]

Electronic Configuration of Cu⁴⁺ is written using these two steps;

Step I:
Write the Electronic Configuration of Copper (Cu).

As Atomic Number of Cu = 29
So,
1s², 2s², 2p⁶, 3s², 3p⁶, 3d¹⁰, 4s¹

Rearranging it in order of increasing orbital energy,

1s², 2s², 2p⁶, 3s², 3p⁶, 4s¹, 3d¹⁰
Or,
Cu = [Ar] 4s¹, 3d¹⁰

Step II:
Now, the Cu⁴⁺ ion has lost 4 electrons, So one electron from 4s and 3 electrons from 3d orbital are removed, The resulting electronic configuration becomes,
Cu⁴⁺ = [Ar] 3d⁷

3 0

3 years ago

Read 2 more answers

Candium forms the ion Sc3+. How many bromite ions could bond with Sc3+, and what would be the chemical formula?

wlad13 [49]

Answer: 3 bromite ions and $Sc(BrO_2)_3$

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here scandium is having an oxidation state of +3 called as $Sc^{3+}$ cation and bromite is an anion with oxidation state of -1 called as $BrO_2^-$ . Thus 1 Scandium ion combines with three bromite ions and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Sc(BrO_2)_3$

7 0

3 years ago

Help please help please help do

Yanka [14]

For the first two
1. Will only give up one atom to be stable
2. Only 2 atoms

3 0

3 years ago