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nataly862011 [7]
3 years ago
11

A barium hydroxide solution is prepared by dissolving 2.06 g of Ba(OH)2 in water to make 32.9 mL of solution. What is the concen

tration of the solution in units of molarity? concentration: 0.364 The barium hydroxide solution is used to titrate a perchloric acid solution of unknown concentration. Write a balanced chemical equation to represent the reaction between barium hydroxide and perchloric acid. chemical equation: 2HCIO4(a Ba(OH2(a)Ba CIO42H2o If 15.9 mL of the barium hydroxide solution was needed to neutralize a 8.50 mL aliquot of the perchloric acid solution, what is the concentration of the acid?
Chemistry
1 answer:
navik [9.2K]3 years ago
4 0

Answer:  1.36 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

To calculate the moles, we use the equation:

moles of solute= \frac{\text {given mass}}{\text {molar mass}}=\frac{2.06g}{171g/mol}=0.0120moles

Molarity=\frac{0.0120\times 1000}{32.9}=0.364M

The balanced reaction between barium hydroxide and perchloric acid:

2HCIO_4+Ba(OH_)2\rightarrow BaCIO_4+2H_2O

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HClO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ba(OH)_2

We are given:

n_1=1\\M_1=?\\V_1=8.50mL\\n_2=2\\M_2=0.364M\\V_2=15.9mL

Putting values in above equation, we get:

1\times M_1\times 8.50=2\times 0.364\times 15.9\\\\M_1=1.36M

Thus the concentration of the acid is 1.36 M

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A system receives 575 ) of heat and delivers 425 ) of work. Calculate the change in the internal energy. AE, of the system.​
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Explanation:

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1. Starting with 9.3 moles of O 2 , how many moles of H 2 S will be needed and how many moles of SO 2 will
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Moles of H₂S needed = 6.2 mol

Moles of SO₂ produced = 6.2 mol

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Number of moles of O₂ = 9.3 mol

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Moles of SO₂ produced = ?

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Now we will compare the moles of SO₂ with both reactant.

                   O₂             :            SO₂

                    3              :               2

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                 H₂S             :            SO₂

                    2              :               2

                   6.2            :          6.2 mol      

So 6.2 moles of  SO₂ are produced.

         

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