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4 years ago

How is the periodic table of the elements arranged

Chemistry

1 answer:

Temka [501]4 years ago

7 0

Answer:

I am pretty sure the answer is c)

Explanation:

Alkali Metals, Alkaline Earth Metals, Transition Metals, Metalloids or Semimetals, Nonmetals, Halogens, and Noble Gases are the groups.

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11. In TLC analysis of ferrocene and acetylferrocene (on silica TLC plate) which prediction is correct: A) ferrocene is more pol

yaroslaw [1]

Answer:

Alternative C would be the correct choice.

Explanation:

The dual compounds were evaluated on something like a TLC plate through three separate additives in conducting a TLC study of ferrocene versus acetylferrocene.
The polar as well as nonpolar ferrocene where nonpolar is about 0.63 with the maximum $R_f$ value, and indeed the polar is somewhere around 0.19 with $R_f$ .
TLC plate (30:1 toluene/ethanol) established with.

The other three choices are not related to the given circumstances. So that option C would be the appropriate choice.

8 0

3 years ago

Water 2270g is heated until it just begins to boil. If the water absorbs 5.51 ×10^5 J of heat in the process, what was the initi

kolbaska11 [484]

Answer:

42.01 °C

Explanation:

<u>Step 1: explain the problem</u>

We have to find the initial temperature, when a certain amount of heat raises this sample of water to its boiling point ( 100 °C)

⇒this amount of heat = 5.51 x 10Δ^5 J

We will use the formule : Q = mcΔ T

with Q = heat transfer ( J)

with m = mass of the substance (g)

with c = specific heat ( J/g °C)

with Δ T = temperature change ( in °C or K)

Water has a specific heat of 4.186 J/g °C

<u>Step 2 : Calculate the initial temperature </u>

We have to rearrange the formule first:

Δ T = Q / mc

In this case we have :

Δ T = 5.51 * 10^5 J / 2270 g * 4.186 J/g °C = 57.99

⇒ The final temperature of the water is the boiling point (100 °C) and the change of temperature is 57.99. This means that the boiling point is 57.99 °C higher than the initial temperature.

This means : Δ T = Tboiling point - Tinitial

Δ T = 57.99 °C = 100 °C - Tinitial

Tinitial = 100 °C - 57.99 °C = 42.01 °C

The initial temperature of the water is 42.01 °C

6 0

4 years ago

A galvanic cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). W

Agata [3.3K]

Answer : The 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Explanation :

Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the voltaic cell or electrochemical cell.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

We are taking the value of standard reduction potential form the standard table.

$E^0_{[Ag^{+}/Ag]}=+0.80V$

$E^0_{[Cu^{2+}/Cu]}=+0.34V$

In this cell, the component that has lower standard reduction potential gets oxidized and that is added to the anode electrode. The second forms the cathode electrode.

The balanced two-half reactions will be,

Oxidation half reaction (Anode) : $Cu(s)\rightarrow Cu^{2+}(aq)+2e^-$

Reduction half reaction (Cathode) : $Ag^{+}(aq)+e^-\rightarrow Ag(s)$

Thus the overall reaction will be,

$Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)$

From this we conclude that, 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Hence, the 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

7 0

4 years ago

A sample of liquid heptane (C7H16) weighing 11.5 g is reacted with 1.3 mol of oxygen gas. The heptane is burned completely (hept

Anna11 [10]

Answer:

a) 0.525 mol

b) 0.525 mol

c) 0.236 mol

Explanation:

The combustion reactions (partial and total) will be:

C₇H₁₆ + (15/2)O₂ → 7CO + 8H₂O

C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O

---------------------------------------------------

2C₇H₁₆ + (37/2)O₂ → 7CO + 7CO₂ + 16H₂O

It means that the reaction will form 50% of each gas.

a) 0.525 mol of CO

b) 0.525 mol of CO₂

c) The molar mass of heptane is: 7*12 g/mol of C + 16*1 g/mol of H = 100 g/mol

So, the number of moles is the mass divided by the molar mass:

n = 11.5/100 = 0.115 mol

For the stoichiometry:

2 mol of C₇H₁₆ -------------- (37/2) mol of O₂

0.115 mol of C₇H₁₆ --------- x

By a simple direct three rule:

2x = 2.1275

x = 1.064 mol of O₂

Which is the moles of oxygen that reacts, so are leftover:

1.3 - 1.064 = 0.236 mol of O₂

5 0

4 years ago

Using complete sentences, explain how to predict the products and balance the reaction between sulfuric acid and potassium hydro

Dahasolnce [82]

The product(s) of the reaction are to be determined given the reactants, sulfuric acid and potassium hydroxide. sulfuric acid is an acid, whereas potassium hydroxide is a basic. The results of this neutralizing process are salt and water.

<h3>What is the reaction between sulfuric acid and potassium hydroxide?</h3>

The result will be, H+ from H₂SO₄ reacts with OH- from KOH to generate H₂O. Also, K+ reacts with SO₄²⁻ to create K₂SO4₄

As a result, the balanced equation will be:

$\rm H_2SO_4 + 2KOH --- > K_2SO_4 + 2H_2O$

Thus, the product(s) of the reaction are to be determined given the reactants, sulfuric acid and potassium hydroxide. Sulfuric acid is an acid, whereas potassium hydroxide is a basic. The results of this neutralizing process are salt and water.

Learn more about potassium hydroxide

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6 0

3 years ago