Answer:
What is the question??
Step-by-step explanation:
Answer:
Since the question doesn't mention in what tide the answer should be, I will be giving a solution to both, the high and low tide. Hope this helps :)
Step-by-step explanation:
Using a cosine function, where time is measured in hours past high
tide: y=4cos30x + 10
Using a cosine function, where time is measured in hours past low
tide: y = 4cos[30(x-6)]+10
Answer:
$325
Step-by-step explanation:
Answer:
The function f(x) is not given, I used a different function but the approach and steps is the same .
Step-by-step explanation:
- Given the function f(x) = 2x2 - 8x + 5
compare with the normal quadratic equation ; ax2 + bx + c = f(x)
- since a is greater than zero i.e a > o {positive}
As such, it has a minimum
hence for minimum value; x = -b/2a
x = -(-8)/2 x 2
x = 8/4 = 2
plugging the values of x in f(x) ; f(2) = 2(2)^2 -8(2) + 5
f(2) = -3, hence it has minimum value and the minimum value is -3
