Let x be your first alloy
2/5x+7/10(30-x)=1/2(30)
4x+210-7x=150
3x=60
x=20
So, you need 20 lbs of the first alloy, and 10 parts of the second to make 30 lbs of half iron and half silver alloy!
Do you see -8x?
Take half of -8 and square it.
So, (-8)/2 = -4.
(-4)^2 = 16
Now add 16 to both sides.
Answer:
=g-1(4)
Step-by-step explanation:
x=3y+8 ---> y=
y=
I believe the correct answer is B. :)
The answer is the last one
