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just olya [345]
2 years ago
14

Write 3 570 000 the following in scientific notation

Mathematics
1 answer:
N76 [4]2 years ago
6 0
3.57* 10 to the sixth power :)
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7th grade girl!<br><br> *(urgent, please help! )*
GenaCL600 [577]

For all the angles, you will have to solve for x

A: 162 = 3x

162/3 = x

54 = x

M: 120 + 2x = 180

2x = 180 - 120

2x = 60

x = 60/2

x = 30

W: 150 = 30x

150/30 = x

5 = x

S: 20 + 2x = 90

2x = 90 - 20

x = 70/2

x = 35

Q : 45 + 5x = 90

5x = 90 - 45

x = 45/5

x = 9

P: not too sure if its 150,

150 + (x+5) = 180

x+5 = 180- 150

x = 30 - 5

x = 25

now you will put all the x values in order. ( i think thats what you supposed to do)

it will be: 5, 9, 25, 30, 35, 54

hope this helps♡♡♡

7 0
3 years ago
F(x) = 3x - 8; f(1)<br> A. 8<br> B. -5 <br> C. -8<br> D. 10
alexgriva [62]
3(1) - 8 = 3 - 8 = -5
just plug in 1 for x that's what f(1) means
6 0
3 years ago
Triangle A is the pre-image in a translation, and triangle B is the image, as shown below.
Lana71 [14]
B. Love miss you have you too she got your
8 0
2 years ago
Help Please<br> Find The Surface Area Of The Prism
snow_lady [41]

Answer:

360 cm^2

Step-by-step explanation:

Find the area of each face of the triangular prism.

Imagine the triangular prism as its net, it is composed with 2 triangular faces (these are tye bases of the prism) and 3 rectangular faces.

Areas of the 2 triangular bases (they are similar triangles):

1/2 x 8 cm x 6 cm = 24 cm^2

24 x 2 = 48 cm^2

Area of the rectangular face:

8 x 13 = 104 cm^2

Area of another rectangular face:

6 cm x 13 cm = 78 cm^2

Area of another rectangular face:

13 cm x 10 cm = 130 cm^2

Add up all the areas of all faces:

48 + 104 + 78 + 130 = 360

So the SA is 360 cm^2

8 0
2 years ago
What is the derivative of the function below?
11111nata11111 [884]

g(x)=4x-\dfrac{1}{4x}=4x-(4x)^{-1}\\\\\\\\g'(x)=\left[4x-(4x)^{-1}\right]'=(4x)'-\left[(4x)^{-1}\right]'=4-[-1(4x)^{-2}]\cdot4\\\\=4+\dfrac{1}{(4x)^2}\cdot4=4+\dfrac{4}{4^2x^2}=\boxed{4+\dfrac{1}{4x^2}}\\\\Used:\\\\(f(x)-g(x))'=f'(x)-g'(x)\\\\.[f(g(x))]'=f'(g(x))\cdot g'(x)\\\\(x^n)'=nx^{n-1}

8 0
3 years ago
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