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3 years ago

The pre–image, A, was dilated about the origin. It was then transformed in another way to get A'.

Mathematics

2 answers:

natulia [17]3 years ago

8 0

It was reflection over y-axis

Elenna [48]3 years ago

6 0

Answer:

reflection over the x-axis

Step-by-step explanation:

i hope this helps

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3 years ago

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Graph the data set {(-1,0.5),(0,1)(1,2)(3,8)(5,32)} Which kind of model best describes the data

bixtya [17]

Answer:

An exponential model can best describe the data

Step-by-step explanation:

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3 years ago

10th of a second : A. 60.34 = 60.3 B. 60.32 = 60.3 C. 60.33 = 60.3 D.

kherson [118]

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3 years ago

HELP PLEASE WILL MARK BRAINLIEST!!

Arte-miy333 [17]

Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

$from \: the \: figure \\ AB = 300 \: ft \: \: \: angle \: C = 60 \:( theta)\: degress \\ in \: triangle \: ABC \: using \: tan \: theta\\ \tan(60) = \frac{opposite \: side}{adjacent \: side} \\ \tan(60) = \frac{300}{BC} \\ \sqrt{3} = \frac{300}{BC} \\ BC = \frac{300}{ \sqrt{3} } \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\ \tan(30 ) =\frac{opposite \: side}{adjacent \: side} \\ \tan(30) = \frac{300}{BD} \\ \frac{1}{ \sqrt{ 3} } = \frac{300}{BD} \\ BD = 300 \sqrt{3} \\ CD = BD - BC \\ = 300 \sqrt{3 } - 100 \sqrt{3} \\ = (300 - 100) \sqrt{3} \\ = 200 \sqrt{3 } \\ = 200 \times 1.732 \\ = 346.4 \: ft$

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THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

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3 years ago

Timothy and 2 of his friends went to see a movie. Each person purchased a $10 movie ticket and a drink. They decided to get 1 la

Ksenya-84 [330]

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3 years ago