Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
<u><em>The complete question is</em></u>
Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B
The picture of the question in the attached figure
Part 1) Write the ratio equivalent to: Sin B
we know that
In the right triangle ABC
----> by SOH (opposite side divided by the hypotenuse)
substitute the values
Part 2) Write the ratio equivalent to: Csc A
we know that
In the right triangle ABC
-----> by SOH (opposite side divided by the hypotenuse)
substitute the values
therefore
Part 3) Write the ratio equivalent to: Cot A
we know that
In the right triangle ABC
-----> by TOA (opposite side divided by the adjacent side)
substitute the values
therefore
We know that
If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment. (Intersecting Secant-Tangent Theorem)
so
ST²=RT*QT
RT=7 in
QT=23+7-----> 30 in
ST²=7*30-----> 210
ST=√210-----> 14.49 in
the answer is
RT=14.49 in
Answer:
B
Step-by-step explanation:
You have separated the figure into three (3) parts. There are two squares (or rectangles on the bottom. Subtract 5 from 8 to find out the length of the side (right side). 8-5=3. Then subtract 3 from 8 (8-3=5). The new length is 5 ft. 5 multiplied by 5 is the area of one of the squares on the bottom (25 ft. squared). Multiply that by two to find the area of both the squares on the bottom (50 ft. squared).
There's also a rectangle on the top. The base is 15 ft. and the height is 3 ft. Remember that you subtracted 5 from 8 to find out the area of the two bottom squares. 15 multiplied by 3 is 45 (ft.)
Add 45 to 50 to get the area of the entire figure. (45+50=95 or 95 ft. squared).
95 ft. squared is the area of the entire figure. Hope this helped you.
Answer:
yes
Step-by-step explanation:
396÷ 9= 44
44×60= 2,640 > 2500
