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masya89 [10]
3 years ago
8

Find the slope of the line that asses through the pair of oints (17,11) and (21,19)

Mathematics
2 answers:
ollegr [7]3 years ago
4 0

Answer:

The slope of the two points is 2. (8/4)

Step-by-step explanation:

thats it

Ludmilka [50]3 years ago
3 0

Answer:

The slope of the two points is 2. (8/4)

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The function h(x) = 12x8 + 49 is an even function. Which transformation of h(x) would result in a function that is neither even
Irina-Kira [14]

Answer:  translation 8 units to the right

Step-by-step explanation:

An even function is a function such that:

h(x) = h(-x)

and the function is odd if:

h(-x) = -h(x)

Now, let's talk about transformations:

A) Reflection over the x-axis:

When we have a point (x,y) and we do a reflection over the x-axis, the reflected point will be:

(x, -y).

Then for the case of a function:

y = h(x).

then the reflection will be:

g(x) = - y = -h(x).

And if h(x) is even, -h(x) is also even, so this is not the correct option.

B) Vertical stretch by a factor of 7.

This is written as:

g(x) = 7*h(x).

then:

g(x) = 7*h(x)

g(-x) = 7*h(-x) = 7*h(x) = g(x)

the transformation is even.

C) Translation of 8 units to the right.

We can write this as:

g(x) = h(x - 8).

Then:

g(-x) = h(-x -8) = h(x + 8)

Then g(-x) is not equal to g(x)

and also g(-x) ≠ -g(x)

So in this case the transformation is neither odd or even.

C)  horizontal compression by a factor of One-half.

This transformation is written as:

g(x) = h( (1/2)*x)

And, similar as the case of the vertical compression, in this case the transformation is also even.

3 0
3 years ago
I'll give brainliest to who can answer this!
bagirrra123 [75]

Answer:

The answer is 96 I hope I helped you

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Step-by-step explanation:

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-6 · f(3) – 6 • g(-1) =
Lubov Fominskaja [6]

Answer:

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Step-by-step explanation:

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3 years ago
(4-8):2-(9-12):3 =<br> Pls
Alenkinab [10]

Are you trying to solve the function operation? If so, your solution is 4 I believe. I don't really have a lot of info on this, but I hope this helps. If not, feel free to comment below and I'll see what I can do to help you further on this. Thanks and good luck!

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2 years ago
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