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bija089 [108]
3 years ago
10

In triangle ABC, angle A is a right angle, and measure of angle B = 45 degrees.

Mathematics
2 answers:
Ghella [55]3 years ago
6 0

Answer:

13√2

Step-by-step explanation:

this is cuz of the 45 45 90 formula

rewona [7]3 years ago
6 0
I think the length of BC is A) 13 sqrt pf 2 ft
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5x + 7 = 2x - 8 can anyone say how to solve please ​
SCORPION-xisa [38]

Answer:

x = - 5

Step-by-step explanation:

Given

5x + 7 = 2x - 8 ( subtract 2x from both sides )

3x + 7 = - 8 ( subtract 7 from both sides )

3x = - 15 ( divide both sides by 3 )

x = - 5

4 0
2 years ago
If a car is traveling at 70 mph, how fast is the car traveling in feet per second? Round to 2 decimal places. (Reminder: there a
alukav5142 [94]

Answer:

264000

Step-by-step explanation:

5 0
3 years ago
Show all work to solve 3x^2 + 5x − 2 = 0
Ratling [72]

Answer:

x=1/3 or x=−2

if i can be brainliest that would be great

Step-by-step explanation:

Step 1: Add 2 to both sides.

3x^2+5x−2+2=0+2

3x^2+5x=2

Step 2: Since the coefficient of 3x^2 is 3, divide both sides by 3.

3x^2+5x/3=2/3

x^2+5/3x=2/3

Step 3: The coefficient of 5/3x is 5/3. Let b=5/3.

Then we need to add (b/2)^2=25/36 to both sides to complete the square.

Add 25/36 to both sides.

x^2+5/3x+25/36=2/3+25/36

x^2+5/3x+25/36=49/36

Step 4: Factor left side.

(x+5/6)^2=49/36

Step 5: Take square root.

x+5/6=±√49/36

Step 6: Add (-5)/6 to both sides.

x+5/6+ −5/6=

−5/6±√49/36x=−5/6±√49/36x=

1/3 or x=−2

3 0
3 years ago
A rectangle has a length of x+7 and a width of 2x-3. If it’s perimeter is 32, what is the value of 3x? A.4/B.12/C.14/D.36/E.42/
Tamiku [17]

Answer:

The correct option is C. 14.

Step-by-step explanation:

First you have that the perimeter of a rectangle = (2·length) + (2·width)

⇒perimeter of a rectangle = [2·( x + 7)] + [2·(2x - 3)]

⇒ 32 = [2·( x + 7)] + [2·(2x - 3)] ⇒ 32 = (2x + 14) + (4x - 6)

⇒ 32 = 6x + 8 ⇒ 32 - 8 = 6x ⇒ 24= 6x ⇒ 24/6 = x ⇒ x = 4. ⇒ 3x= 12.

7 0
3 years ago
If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
2 years ago
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