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777dan777 [17]
3 years ago
12

Question 2 An exponential model y = a.6 passes through the points (0,9) and (3,243). What are the values of a and b?​

Mathematics
1 answer:
weqwewe [10]3 years ago
8 0

Answer:

a = 9, b = 3

Step-by-step explanation:

The exponential function is

y = a b^{x}

Find a and b by using the points it passes through

Using (0, 9 ) then

9 = a b^{0} ( b^{0} = 1 )

a = 9

y = 9 b^{x}

Using (3, 243 ) then

243 = 9b³ ( divide both sides by 9 )

27 = b³ ( take the cube root of both sides )

b = \sqrt[3]{27} = 3

y = 9(3)^{x} ← exponential equation

You might be interested in
5 pounds of bananas for $1.97 for 3 pounds of bananas for $1.05 which is better to buy
andrew11 [14]

Answer:

<h3>3 pounds for $1.05 is better since it is 35 cents a pound as opposed to 39 cents a pound for the other product.</h3>

Step-by-step explanation:

We need to find the unit rate. This found by dividing the price by the number of bananas so we get the price for 1 pound of bananas.

$1.97/5 = $0.39

$1.05/3 = $0.35

<h3>3 pounds for $1.05 is better since it is 35 cents a pound as opposed to 39 cents a pound for the other product.</h3>
8 0
3 years ago
2(a-3)÷(a-4)(a-5)+a-1÷(3-a)(a-4)+a-2÷(5-a)(a-3) simplify.​
Arlecino [84]

<u><em>I'm almost confident that I did this wrong, but i tried...</em></u>

Answer:

4a-9 ÷ -19

Step-by-step explanation:

(It was easier for me to put it in fractions)

\frac{2(a-3)}{(a-4)(a-5)} + \frac{a-1}{(3-a)(a-4)} + \frac{a-2}{(5-a)(a-3)}        (3-a) (a-4) + (5-a) (a-3)

\frac{2a-6}{(a-4)(a-5)} + \frac{a-1}{(3-a)(a-4)} +  \frac{a-2}{(5-a)(a-3)}      3 - a · a - 4 + 5 - a · a - 3

    \frac{2a-6}{(2a-20)} + \frac{a-1}{(3-a)(a-4)} + \frac{a-2}{(5-a)(a-3)}               3 - a + 1 - a - 3

   \frac{2a-6+a-1+a-2}{(2a-20)+(3-a)(a-4)+(5-a)(a-3)}                        1 - a - a

                 \frac{4a-9}{2a-20+1-2a}                                       1 - 2a

                   \frac{4a-9}{2a-19-2a}

                      \frac{4a-9}{-19}

8 0
3 years ago
use the explixt rule to find the 25th term of each sequence.Assume that the domain of each function is the set of whole numbers
Rom4ik [11]
The answer to your question is 12
3 0
3 years ago
G(–2) = –2(–2)2 + 3(–2) – 5<br> g(–2) = –2(4) – 6 – 5<br> g(–2) =
Xelga [282]

Answer:

G(-2)=-8-6-5=-

Step-by-step explanation:

Issue talk to my fist

3 0
4 years ago
Given: Q = 7m + 3n, R = 11 - 2m, S = n + 5, and T = -m - 3n + 8.
Margarita [4]

If you would like to simplify Q + S - T, you can do this using the following steps:<span>

Q = 7m + 3n, 
R = 11 - 2m, 
S = n + 5,
T = -m - 3n + 8

</span>Q + S - T = 7m + 3n + n + 5 - (-m - 3n + 8) = 7m + 3n + n + 5 + m + 3n - 8 = 8m + 7n - 3

The correct result would be <span>8m + 7n - 3.</span>

5 0
3 years ago
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